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A farmer has a field that measures 1000 ft wide by 2000 ft long. There is an untillable strip 20 ft wide on the inside edge of the field, and a 30 ft wide untillable strip bisects the field into two squares (approximate). Approximately what percentage of the field is tillable?
A. 98%
B. 93%
C. 91%
D. 90%
E. 88%
A. 98%
B. 93%
C. 91%
D. 90%
E. 88%
28 May 2011, 08:51
Kudos
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28 May 2011, 04:42
Kudos
Bookmarks
Actually you can solve the problem pretty fast by using following approach:
1. one shorter inside strip with width of 20 ft takes 20/2000 = 1% of field
2. There is 2 short strips, 2 long strips (twice as long as shorts ones) and one short but wider strip that equals 30/20 = 1.5 short strips.
3. Approximately we have 2 + 2*2 + 1.5 = 7.5 short strips --> ~ 7.5% or 92.5%
4. As we didn't take into account overlaps between strips it will be slightly higher than 92.5%.
Or you can use calculations but I think it will take more time:
\(%=100%*\frac{2*(1000-2*20)*(1000-20-\frac{30}{2})}{1000*2000} = 0.9264\)
1. one shorter inside strip with width of 20 ft takes 20/2000 = 1% of field
2. There is 2 short strips, 2 long strips (twice as long as shorts ones) and one short but wider strip that equals 30/20 = 1.5 short strips.
3. Approximately we have 2 + 2*2 + 1.5 = 7.5 short strips --> ~ 7.5% or 92.5%
4. As we didn't take into account overlaps between strips it will be slightly higher than 92.5%.
Or you can use calculations but I think it will take more time:
\(%=100%*\frac{2*(1000-2*20)*(1000-20-\frac{30}{2})}{1000*2000} = 0.9264\)
