|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
26 May 2017, 04:43
Kudos
Bookmarks
Is the number of the average (arithmetic mean) attendees of 3 performances equal to the median number of attendees of the 3 performances?
(1) The median number of attendees of 3 the performances is 39
(2) The range of attendees of 3 the performances is 39
(1) The median number of attendees of 3 the performances is 39
(2) The range of attendees of 3 the performances is 39
26 May 2017, 04:45
Kudos
Bookmarks
Official Solution:
If you take the 1st step of the variable approach and modify the original condition and the question, and assume the number of attendees who attend to the 3 performances as a, M, and c \((a < M < c)\), you get \(\frac{a+M+c}{3} = M\)?, \(a + M + c = 3M\), \(a+c=2M\), or \(c = 2M - a\). If so, you get \(c - a = 2M - a - a = 2(M - a)\), and \(range = c - a = 2(M - a) = even\)?. In the case of con 2), \(range = 39 = odd\), so it is no, but according to CMT 1, no can also be the answer, so it is sufficient. In the case of con 1), \((a, M, c) = (38, 39,40)\) is yes, and \((a, M, c) = (38, 39, 41)\) is no, hence not sufficient. Therefore, the answer is B.
Answer: B
If you take the 1st step of the variable approach and modify the original condition and the question, and assume the number of attendees who attend to the 3 performances as a, M, and c \((a < M < c)\), you get \(\frac{a+M+c}{3} = M\)?, \(a + M + c = 3M\), \(a+c=2M\), or \(c = 2M - a\). If so, you get \(c - a = 2M - a - a = 2(M - a)\), and \(range = c - a = 2(M - a) = even\)?. In the case of con 2), \(range = 39 = odd\), so it is no, but according to CMT 1, no can also be the answer, so it is sufficient. In the case of con 1), \((a, M, c) = (38, 39,40)\) is yes, and \((a, M, c) = (38, 39, 41)\) is no, hence not sufficient. Therefore, the answer is B.
Answer: B
Moderator:
