Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
If the sum of all positive factors of an integer n is 2n, n is a perfect number. For example, the factors of 6 are 1, 2, 3, and 6, and from the sum \(1 + 2 + 3 + 6 = 12 = 2*6\), the sum of the factors of 6 becomes \(12 = 2*6\), thus 6 is the first perfect number. Then, what is the number of factors of the second perfect number?
If the sum of all positive factors of an integer n is 2n, n is a perfect number. For example, the factors of 6 are 1, 2, 3, and 6, and from the sum \(1 + 2 + 3 + 6 = 12 = 2*6\), the sum of the factors of 6 becomes \(12 = 2*6\), thus 6 is the first perfect number. Then, what is the number of factors of the second perfect number?
A. 4 B. 5 C. 6 D. 8 E. 12
In general, perfect number is \((2^{n-1})(2^{n}-1)\) when n=prime number. In other words, when n=2, \((2^{2-1})(2^{2}-1) = (2)(3) = 6\) is the first perfect number. The 2nd perfect number is when n=3, and with substitution, you get \((2^{3-1})(2^{3}-1) = (4)(7) = 28\). In other words, the sum of all factors of \(28 = 1+2+4+7+14+28 = 2(28)\), hence it is a perfect number. From \(28 = (2^{2})(7^{1})\), the number of factors is \((2+1)(1+1) = 6\). The answer is C.