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cfc198
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A pipe is filling a tank of 200 litres capacity at 5 litres/hr. Becaus 23 Oct 2019, 03:49
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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35% (medium)

Question Stats:

81% (01:32) correct 19% (01:30) wrong based on 26 sessions

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A pipe is filling a tank of 200 litres capacity at 5 litres/hr. Because of a leak, it takes 80 hours more to fill the tank. What is the rate in litres/hr at which the water is leaking?

(A) 60
(B) 3
(C) 3.33
(D) 80
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C
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A pipe is filling a tank of 200 litres capacity at 5 litres/hr. Becaus 27 Oct 2019, 23:23
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the pipe would have filled water in 200/5 = 40 hours if leak was not there.

the pipe took 80 hours more because of leak
=> the pipe worked for 40+80 hrs= 120 hrs and filled 120*5 litres = 600 litres

=> 600-200= 400 litres of water leaked out in 120 hours
Rate of leakage per hour = 400/120

= 3.33 ltr/hr

(C) Ans
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A pipe is filling a tank of 200 litres capacity at 5 litres/hr. Becaus 30 Jun 2020, 05:44
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If there was no leak then at the rate of 5l/hr, the tank would have been filled in 40 hours.
But it took 80 hours more.
Total time taken to fill the tank = 120 hours.
Rate at which the tank was being filled = \(\frac{200}{120} = \frac{5}{3}\) l/hr

The rate at which the water was leaking = \(5 - \frac{5}{3} = \frac{10}{3} = 3.33\)

OA, C
cfc198
A pipe is filling a tank of 200 litres capacity at 5 litres/hr. Because of a leak, it takes 80 hours more to fill the tank. What is the rate in litres/hr at which the water is leaking?

(A) 60
(B) 3
(C) 3.33
(D) 80
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A pipe is filling a tank of 200 litres capacity at 5 litres/hr. Becaus 30 Jun 2020, 05:59
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In such questions, it always helps to treat it like a distance-time-speed problem. In other words, the rate, amount of work and time play the respective roles of speed, distance and time in questions of motion.

Assign signs to the rate based on whether the tank is being filled or emptied. For instance, in this question:

Time taken by pipe for filling tank = Amount of work/Rate = Capacity of tank/Rate = 200/5 = 40 hrs
Let the rate at which the tank leaks = x litres/hr

When both are at work (pipe and leak), the effective rate of filling the tank = Rate of pipe (filling) - Rate of leak (emptying) = 5 - x litres/hr
When both are at work, time taken to fill the tank = 40 + 80 = 120 hrs

We know that, Time = Work /Rate

Plugging in the respective values, we have:

120 = 200/(5 - x)
==> 120(5 - x) = 200
==> 600 - 120x = 200
==> 600 - 200 = 120x
==> x = 3.33 litres/hr

Answer = (C)

Hope this helps.