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Updated on: 03 Dec 2023, 02:53
Originally posted by Sajjad1994 on 07 Sep 2020, 01:37.
Last edited by BottomJee on 03 Dec 2023, 02:53, edited 2 times in total.
Last edited by BottomJee on 03 Dec 2023, 02:53, edited 2 times in total.
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Dropdown 1: Newspaper B
Dropdown 2: 1/24
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
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Question Stats:
86% (01:25) correct
14%
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wrong
based on 369
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The diagram below shows the number of citizens who read newspapers in country Z. There are three types of newspapers in country Z: Newspaper A, Newspaper B, and Newspaper C.
1. Suppose the popularity of a newspaper is characterized by the number of citizens who read the newspaper, then is the LEAST popular newspaper.
2. If one citizen is randomly selected from the newspaper readers above, the probability that a person reads all of the three newspapers is .
12.jpg [ 53.98 KiB | Viewed 6700 times ]
2. If one citizen is randomly selected from the newspaper readers above, the probability that a person reads all of the three newspapers is .
Attachment:
12.jpg [ 53.98 KiB | Viewed 6700 times ]
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Official Answer
Dropdown 1: Newspaper B
Dropdown 2: 1/24
07 Sep 2020, 07:13
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From the diagram, the basic data that we can get are:
Those who read newspaper A = Only A + Only A and B + Only A and C + A and B and C = 7 + 2 + 3 + 1 = 13
Those who read newspaper B = Only B + Only A and B + Only B and C + A and B and C = 5 + 2 + 1 + 1 = 9
Those who read newspaper C = Only C + Only B and C + Only A and C + A and B and C = 5 + 1 + 3 + 1 = 10
Total News paper readers = Only A + Only B + Only C + Only A and B + Only A and C + Only B and C + All three = 24
Question A: The least popular is Newspaper B with 9M readers.
Option B
Question B: Probability that a person reads all three newspapers.
\(Probability = \frac{Favorable \space Outcomes}{Total Outcomes} = \frac{1}{24}\)
Option C
Question C: The person reads either A or B or C only.
\(Probability = \frac{Favorable \space Outcomes}{Total Outcomes} = \frac{5 \space + \space 5 \space + \space 7}{24}= \frac{17}{24}\)
Option B
Question D: The person reads exactly 2 of the newspapers.
\(Probability = \frac{Favorable \space Outcomes}{Total Outcomes} = \frac{2 \space + \space 1 \space + \space 3}{24}= \frac{6}{24}= \frac{1}{4}\)
Option B
Question E: The ratio of the most popular to the least popular = \(\frac{Newspaper \space A}{Newspaper \space B} = \frac{13}{9}\)
Option C
Arun Kumar
Those who read newspaper A = Only A + Only A and B + Only A and C + A and B and C = 7 + 2 + 3 + 1 = 13
Those who read newspaper B = Only B + Only A and B + Only B and C + A and B and C = 5 + 2 + 1 + 1 = 9
Those who read newspaper C = Only C + Only B and C + Only A and C + A and B and C = 5 + 1 + 3 + 1 = 10
Total News paper readers = Only A + Only B + Only C + Only A and B + Only A and C + Only B and C + All three = 24
Question A: The least popular is Newspaper B with 9M readers.
Option B
Question B: Probability that a person reads all three newspapers.
\(Probability = \frac{Favorable \space Outcomes}{Total Outcomes} = \frac{1}{24}\)
Option C
Question C: The person reads either A or B or C only.
\(Probability = \frac{Favorable \space Outcomes}{Total Outcomes} = \frac{5 \space + \space 5 \space + \space 7}{24}= \frac{17}{24}\)
Option B
Question D: The person reads exactly 2 of the newspapers.
\(Probability = \frac{Favorable \space Outcomes}{Total Outcomes} = \frac{2 \space + \space 1 \space + \space 3}{24}= \frac{6}{24}= \frac{1}{4}\)
Option B
Question E: The ratio of the most popular to the least popular = \(\frac{Newspaper \space A}{Newspaper \space B} = \frac{13}{9}\)
Option C
Arun Kumar
15 Jun 2025, 00:56
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