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If there are 5 cars and they only collide with each other, each car can be involved in at most 4 accidents. The total number of unique accident pairings is 5C2 = 10.

By the same logic, to account for 350,000 accidents, the minimum number of cars involved would be 70,000, since 5 cars produce 10 accidents.

Any suggestions where i may be wrong or issues with my approach?
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If there are 5 cars and they only collide with each other, each car can be involved in at most 4 accidents. The total number of unique accident pairings is 5C2 = 10.

By the same logic, to account for 350,000 accidents, the minimum number of cars involved would be 70,000, since 5 cars produce 10 accidents.

Any suggestions where i may be wrong or issues with my approach?
Your method does not give 72,000 cars. Let’s check it carefully: with 5 cars, the number of unique pair accidents is 5C2 = 10. Scaling that logic, for 360,000 accidents we get 360,000/10 * 5 = 180,000 cars. So your approach actually produces a larger number, not a smaller one.
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spent time on thinking about what automobiles accident mean , is it between 2 cars or can be with one car only(like car and a tree) , if it is between 2 car we need is it reported as 1 accident or 2 accident. if we presume it is one per eevnt , then taking single car accident will help to minimize.
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