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03 Dec 2023, 03:52
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Dropdown 1: 90 thousand
Dropdown 2: Choose this one
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
69% (02:06) correct
31%
(02:35)
wrong
based on 1467
sessions
History
Date
Time
Result
Not Attempted Yet
6. Please choose this drop-down as a Graphs question needs to have 2 .
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Official Answer
Dropdown 1: 90 thousand
Dropdown 2: Choose this one
16 Feb 2024, 07:16
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car in accidents = Accidents/ ("accidents per cars")
Accidents = 36*10k = 360k
"accidents per cars" <= 4
car in accidents = Accidents/ ("accidents per cars") >= 360k/4 = 90k
Observation: the first time I solved this question, I got confused on the wording of this question, but there where only three numbers to use: 360k accidents, 4 accidents per car, and 11M cars in 1993. Since the question asks for "car in accidents", we have two options: to use 11M; or to use a combination of "4 accidents per car" and 360k accidents. 11M doesnt give any clue about the possible answers in the droplist. the other alternative does. using Dimensional analysis we obtained a option in the droplist: 360k accidents/(4 accidents per car) = 90k cars.
Accidents = 36*10k = 360k
"accidents per cars" <= 4
car in accidents = Accidents/ ("accidents per cars") >= 360k/4 = 90k
Observation: the first time I solved this question, I got confused on the wording of this question, but there where only three numbers to use: 360k accidents, 4 accidents per car, and 11M cars in 1993. Since the question asks for "car in accidents", we have two options: to use 11M; or to use a combination of "4 accidents per car" and 360k accidents. 11M doesnt give any clue about the possible answers in the droplist. the other alternative does. using Dimensional analysis we obtained a option in the droplist: 360k accidents/(4 accidents per car) = 90k cars.
General Discussion
09 Jun 2024, 10:08
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Total no of accidents = 36*10^4
Maximum no of accidents per car = 4
minimum no. of cars = 36*10^4 / 4 = 90,000
Maximum no of accidents per car = 4
minimum no. of cars = 36*10^4 / 4 = 90,000
