mkeshri185
I didn't get why D is the answer...
By the time the ions again reach the dee gap, the sign of the electric potential on the dees is reversed, so that now the ions are attracted toward the opposite dee
It is given in the passage.
It says ion was +ve and it get attracted towards -ve dee . So first part is fine
Now passage says Electric potential on Dees is reversed. Which means now they are +ve dees. How can ions get attracted to -ve dee again?
Start: - Dee A = negative, Dee B = positive.
- Positive ion ----> attracted to Dee A (negative).
Ion moves inside Dee A (magnetic field bends it in semicircle), emerges at gap.
Electric potential reverses:- Now Dee A = positive, Dee B = negative.
- Ion -----> attracted to Dee B (which is now negative).
So in one full cycle (gap ---> Dee A ---> gap ---> Dee B):
- First half: attracted to negative Dee A.
- Second half: attracted to negative Dee B.
What
(D) says
(D) A positively charged ion is attracted to a negative dee, then attracted to a negative dee.“Then” here means after one half-turn, the second attraction is to the other dee, which is negative after reversal. So yes, both times it’s attracted to a negative dee, just a different dee each half-revolution.
The passage says after reversal
“ions are attracted toward the opposite dee” that opposite dee is now negative (because potentials swapped).
So
(D) is consistent, while others are factually wrong.