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22 Apr 2024, 12:44
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Question Stats:
100% (01:04) correct
0% (00:00) wrong based on 1 sessions
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r, s, and t are three consecutive odd integers such that r<s<t
Quantity A
r + s + 1
Quantity B
s + t - 1
Quantity A
r + s + 1
Quantity B
s + t - 1
03 May 2024, 18:04
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Just pick 3 consecutive odd numbers such that the according stem condition
\(3 < 5 < 7\)
\(3+5+1=9\)
\(7+5-1=11\)
Answer is \(B\)
\(3 < 5 < 7\)
\(3+5+1=9\)
\(7+5-1=11\)
Answer is \(B\)
01 Jul 2024, 12:15
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Official Explanation
You are given that three numbers, r, s, and t, are consecutive odd integers and that r<s<t. This means that if you express the three consecutive odd integers in terms of r, they are r, r + 2, and r + 4.
One way to approach this problem is to set up a placeholder relationship between the two quantities and simplify it to see what conclusions you can draw.
In the last step of the simplification, you can easily see that 3<5. If you follow the simplification steps in reverse, you can see that the placeholder in each step remains unchanged, so you can conclude that Quantity B is greater than Quantity A, and the correct answer is Choice B.
Note that in this solution, the fact that r is odd is not used; what is used is the fact that the consecutive odd integers differ by 2.
You are given that three numbers, r, s, and t, are consecutive odd integers and that r<s<t. This means that if you express the three consecutive odd integers in terms of r, they are r, r + 2, and r + 4.
One way to approach this problem is to set up a placeholder relationship between the two quantities and simplify it to see what conclusions you can draw.
- Simplification 1: Begin simplifying by expressing s and t in terms of r. The steps in this simplification can be done as follows. In the last step of the simplification, you can easily see that . If you follow the simplification steps in reverse, you can see that the placeholder in each step remains unchanged, so you can conclude that Quantity B is greater than Quantity A, and the correct answer is Choice B.
- Simplification 2: Since the number s appears in both quantities, you can begin the simplification by subtracting s from both sides of the relationship and then express t in terms of r. The steps in this simplification can be done as follows.
In the last step of the simplification, you can easily see that 3<5. If you follow the simplification steps in reverse, you can see that the placeholder in each step remains unchanged, so you can conclude that Quantity B is greater than Quantity A, and the correct answer is Choice B.
Note that in this solution, the fact that r is odd is not used; what is used is the fact that the consecutive odd integers differ by 2.
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