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27 Sep 2024, 11:32
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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The length of each side of rectangle R is an integer, and the area of R is 36.
Quantity A
The number of possible values of the perimeter of R
Quantity B
6
Quantity A
The number of possible values of the perimeter of R
Quantity B
6
23 Feb 2025, 03:56
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OE
Because the length of each side of rectangle R is an integer and each length is a factor of the area 36, there are 5 possible rectangles: a 1×36 rectangle, a 2×18 rectangle, a 3×12 rectangle, a 4×9 rectangle, and a 6×6 rectangle.
The perimeter of the 1×36 rectangle is 2(1 + 36), or 74.
The perimeter of the 2×18 rectangle is 2(2 + 18), or 40.
The perimeter of the 3×12 rectangle is 2(3 + 12), or 30.
The perimeter of the 4×9 rectangle is 2(4 + 9), or 26.
The perimeter of the 6×6 rectangle is 2(6 + 6), or 24.
Since each of the 5 possible rectangles has a different perimeter, Quantity A, the number of possible values of the perimeter, is 5. Since Quantity B is 6, the correct answer is Choice B.
Because the length of each side of rectangle R is an integer and each length is a factor of the area 36, there are 5 possible rectangles: a 1×36 rectangle, a 2×18 rectangle, a 3×12 rectangle, a 4×9 rectangle, and a 6×6 rectangle.
The perimeter of the 1×36 rectangle is 2(1 + 36), or 74.
The perimeter of the 2×18 rectangle is 2(2 + 18), or 40.
The perimeter of the 3×12 rectangle is 2(3 + 12), or 30.
The perimeter of the 4×9 rectangle is 2(4 + 9), or 26.
The perimeter of the 6×6 rectangle is 2(6 + 6), or 24.
Since each of the 5 possible rectangles has a different perimeter, Quantity A, the number of possible values of the perimeter, is 5. Since Quantity B is 6, the correct answer is Choice B.
