Official ExplanationIf the two known sides of length 4 and 5 are placed perpendicular to each other, they can be used as the base and height to compute the triangle’s area as,

by the formula area =

Now imagine using the side of length 5 as the base and swiveling the side of length 4, about a hinge at the vertex of the triangle where these sides intersect. The resulting height, h, in the figures above, is less than 4, whether the triangle is acute or obtuse. (It should be obvious that h < 4 in the two diagrams at right, above, but if you are not sure why, observe that h is the leg of a smaller right triangle, which has hypotenuse = 4.) Then the area of the right triangle, 10, is the maximum possible, and (B), 11 is greater.
Answer: B Attachment:
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Attachment:
GMAT-Club-Forum-ge2r5ik1.png [ 15.43 KiB | Viewed 210 times ]