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I know this post is quite old, but I'm just discovering this forum (thankfully after only being 1 week into studying). I genuinely am surprised to see such great resources on here and I'm feeling more confident, even after just discovering gmatclub, that I'll get a good score.

I have a question about the downloadable sheet. I'm kind of confused with how it's ordered and why some of the items are included. Why are some fractions and some exponents on here, but others aren't? Is there a reason for these particular ones to be remembered? When a fraction or percentage is listed, should we be memorizing the decimal, percentage and fraction versions of each of them?

For the last three lines, why is it important to know the multiples of 12, 15 and 8 over other ones?

The doc gives some arithmetics which one will frequently need while solving the GMAT questions. Though I agree that some useful staff is missing and presence of some other things is debatable.

As for the percentages, it's good to know fractional as well as decimal representation of some of them.
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Now, what does this mean:

Area of Isosceles Triangle = 1/2[(leg)^2]
(from Geometry Formulas.pdf)

I haven't been able to give myself any convincing explanation of this formula...
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I'd also add one more element to Coordinate geometry. The coordinates of a point P on line joining two points A(x1,y1) and B(x2,y2) such that PA:PB is in the ration m:n would be ((mx2+nx1)/(m+n),(my2+ny1)/(m+n)).
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I'd just caution test takers that the GMAT is not a test of how many formulas you can memorize, and whether you can plug numbers into them. Especially at the higher difficulty levels, it's a test of how well you think about mathematical concepts. I could write all the GMAT Quant facts I ever use on one sheet of paper (if I draw the Geometry diagrams small enough :) ). Most prep company materials I've seen advise memorizing far too many things, things that won't ever help on the actual test.
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Thanks for this memory sheet, very useful!


However I believe some formulas, details might be added...

Angles of a polygons (n-2)* 180, angles inscribed in a circle (compared to central angle there a section about it in the VERITAS Prep book)


Also I did not see two real IMPORTANT triangles sides ratio:

3:4:5
5:12:13

Good you put the formula for the equilateral triangle (which is not given in the OG and allow you to gain so much time)

I found formula I did not know! :-) Thank you for sharing
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Added TTP's 15-page PDF with required formulas and illustrations.

https://blog.targettestprep.com/gmat-equation-guide/

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Hi,

I believe this to be one of the most important hacks to learn by heart: Pythagorean triple.
A Pythagorean triple is a triple of positive integers a, b, and c such that a right triangle exists with legs a,b and hypotenuse c. By the Pythagorean theorem, this is equivalent to finding positive integers a, b, and c satisfying
a^2+b^2=c^2. Please find below the ones that are most popular to memorize:

3, 4, 5
5, 12, 13
7, 24, 25
8, 15, 17
12, 35, 37

Remember that this only works for right triangles. Good luck :)
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AtifS
Guys! I just found another way of checking whether a number is divisible by 8 or not ( the rule is same but another approach or route ). It's for a number with more than two digits.

Let's take 1936
1) First of all check whether last two digits of the number are divisible by 4 or not.
For 1936, we do this way 36/4=9

2) If it is divisible by 4 then add the quotient to the 3rd last digit of the number and if the sum of them is divisible by 2 then the whole number is divisible by 8.

--> 9 (quotient)+ 9 ( 3rd digit from right)= 18, and -->18/2=9
So the whole number is divisible by 8.

Once you understand it and do a little practice, you'll find it easy and fast.
**You can try other numbers to see whether it is true or not
Hope it helps!

Hello everyone,
I'm a newcomer. Just decided to learn GMAT for a week. Thank you so much for the tip. I try to solve the logic.
Let's take an interger n = Abcd (A can be any number) Abcd = 1000A + 100b + 10c + d.
If last two digit is divisible by 4: 10c + d = 4x. Then we have: Abcd = 125*8A + 100b + 4x
If sum of the third digit and x is divisible by 2: b+x=2y or x = 2y-b
Abcd = 125*8A + 100b + 4(2y-b) = 125*8A + 96b + 8y = (125A +12b+y)*8

So n is divisible by 8.
Actually simply just put if the last 3 digits is divisible by 8 then the whole number is, too.
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