jatin2003 wrote:
How do we get the radius by combining statements 1 and 2 ?, please
Statement 1 tells us that the corresponding ars, QRS, accounts for 1/6th of the circumference, implying that the angle enclosing the arc is 1/6th of the circle, i.e. 360/6 = 60 degrees.
Now, the nature of the triangle enclosed between the center of the circle, let's call it O, and points Q and S is such that angles at point Q, and point S are equal to each other, because sides, OQ and OS correspond to the radius of the circle.
From Statement 1, we know that the angle at the center of the circle is 60 degrees, therefore the other two angles can be calculated the following:
180-60=2x
x=60
Triangle 60-60-60 is an equilateral triangle ergo, sides are-6-6-6 (Statement 2), therefore the radius is of the circle is 6.
Circumference = 2rPi = pi*12