Bunuel wrote:

What is the probability of rolling three fair dice and having all three dice show an odd number?

A. 5/8

B. 1/8

C. 1/36

D. 1/108

E. 1/216

Favourable Outcome = ( ie - 1, 3 , 5 )

Total Outcome = 6 ( ie, 1 , 2 , 3 , 4 , 5 , 6 )

Required Probability = \(\frac{3}{6} = \frac{1}{2}\)

Hence, the Probability of getting an odd number in 3 outcomes is \((\frac{1}{2})^3\) = \(\frac{1}{8}\)

Hence, Correct answer will be (B) \(\frac{1}{8}\)
_________________

Thanks and Regards

Abhishek....

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