Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
66% (01:23) correct
34%
(01:26)
wrong
based on 561
sessions
History
Date
Time
Result
Not Attempted Yet
Tough and Tricky questions: Probability.
What is the probability that it will rain on each of the next 3 days if the probability of raining on any single day is the same in that period? (Assume that the probability of rain on one day is independent of the probability of rain on any other day).
(1) The probability of no rain throughout the first two days is 36%.
(2) The probability of rain on the third day is 40%.
Edit: Original question is below:
What is the probability that it will rain on each of the next 3 days if the probability of raining on any single day is the same in that period?
(1) The probability of no rain throughout the first two days is 36%.
(2) The probability of rain on the third day is 40%.
Edited after Ian Stewart's comment below
What is the probability that it will rain on each of the next 3 days if the probability of raining on any single day is the same in that period?
(1) The probability of no rain throughout the first two days is 36%.
(2) The probability of rain on the third day is 40%.
Edited after Ian Stewart's comment below
03 Nov 2014, 13:50
Kudos
Bookmarks
What is the probability that it will rain on each of the next 3 days if the probability of raining on any single day is the same in that period?
(1) The probability of no rain throughout the first two days is 36%.
(2) The probability of rain on the third day is 40%.
A = rain
B = no rain
What is \(P(A)*P(A)*P(A) = P(A)^3\) ?
(1) The probability of no rain throughout the first two days is 36%.
\(P(B)*P(B) = 0,36\) ---> \(P(B) = 0,6\)
\(P(A) = 1 - P(B) = 1 - 0.6 = 0.4\)
\(P(A)^3 = 0,4^3 = 0,064\)
SUFFICIENT
(2) The probability of rain on the third day is 40%.
\(P(A) = 0,4\)
\(P(A)^3 = 0,4^3 = 0,064\)
SUFFICIENT
Correct answer is D
(1) The probability of no rain throughout the first two days is 36%.
(2) The probability of rain on the third day is 40%.
A = rain
B = no rain
What is \(P(A)*P(A)*P(A) = P(A)^3\) ?
(1) The probability of no rain throughout the first two days is 36%.
\(P(B)*P(B) = 0,36\) ---> \(P(B) = 0,6\)
\(P(A) = 1 - P(B) = 1 - 0.6 = 0.4\)
\(P(A)^3 = 0,4^3 = 0,064\)
SUFFICIENT
(2) The probability of rain on the third day is 40%.
\(P(A) = 0,4\)
\(P(A)^3 = 0,4^3 = 0,064\)
SUFFICIENT
Correct answer is D
General Discussion
05 Nov 2014, 13:20
Kudos
Bookmarks
Bunuel
Raining on any day is an independent event. Lets take the probability of raining on a single day as 1/x. Therefore probability of no rain on that day is [1-1/x] .
what is asked is if 1/x * 1/x * 1/x can be found out
[1] Probability of No rain in the first two days = 36%
i.e [1-1/x] * [1-1/x] = 36% . From this we can find [1/x]^3. Therefore sufficient.
[2] Probability of rain on third day is 40%.
1/x is 40% . Probability is same for all the days. So [1/x]^3 can be found out. Therefore sufficient.
Hence D.
-------------
Please give kudos if this helps.
