stonecold wrote:

What is the remainder when 99009900990099000065 is divided by 32

A)zero

B)one

C)two

D)three

E)four

we could easily eliminate few choices...

it can't be zero, as 32 multiplied by any number would not yield another number with units digit equal to 5.

Moreover, it can't be any EVEN number as a remainder, because odd - even = odd.

C and E are out.

between B and D:

32 * xx2 - then one

32 * xx1 - then three

to be divisible by 32, it must be divisible by 2 four times.

99009900990099000000 is clearly divisible by 32.

64 is divisible by 32 too

therefore, 99009900990099000064 is divisible by 32. therefore, one is the remainder.