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# What is the value of y in the system above?

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What is the value of y in the system above? [#permalink]
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my solution of

x+2y+3z=2
x+y-z=0
2x+2y-z=1

1. subtract equation#2 from equation#1 because we do not need x, we look for y

y+4z=2

2. to eliminate x in second pair multiply equation#2 by -2 and add equation#2 to equation#3

z=1

3. substitute z with 1 and get y=-2
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Re: What is the value of y in the system above? [#permalink]
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Re: What is the value of y in the system above? [#permalink]
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