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27 Jun 2023, 11:00
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B
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Difficulty:
35%
(medium)
Question Stats:
69% (01:22) correct
31%
(01:22)
wrong
based on 158
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When 2 dices tossed, what is the probability that 2 numbers faced have difference 2?
A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 5/9
A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 5/9
27 Jun 2023, 11:08
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Given: 2 Dices are tossed.
Asked: P(2 numbers faced have difference 2) =?
Solution: Total cases = 6\(^2\) = 36
Favorable cases - (1,3), (2,4), (3,5), (4,6), (3,1), (4,2), (5,3), (6,4) = 8 cases.
P(2 numbers faced have difference 2) = \(\frac{8}{36}\) = \(\frac{2}{9}\)
Answer: B.
Asked: P(2 numbers faced have difference 2) =?
Solution: Total cases = 6\(^2\) = 36
Favorable cases - (1,3), (2,4), (3,5), (4,6), (3,1), (4,2), (5,3), (6,4) = 8 cases.
P(2 numbers faced have difference 2) = \(\frac{8}{36}\) = \(\frac{2}{9}\)
Answer: B.
Archit3110
Major Poster
27 Jun 2023, 11:26
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total pairs with difference of 2 ; ( 1,3) ( 2,4) (3,5) ( 4,6) ; 4
2c1 ways of getting either of dices
total numbers 6^2
4 * 2c1 / 6^2
8/36 ; 2/9
option B
2c1 ways of getting either of dices
total numbers 6^2
4 * 2c1 / 6^2
8/36 ; 2/9
option B
Bunuel
