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# When 2 fair dice are tossed, what is the probability that the differen

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Math Revolution GMAT Instructor
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When 2 fair dice are tossed, what is the probability that the differen [#permalink]

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01 Dec 2017, 00:13
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25% (medium)

Question Stats:

78% (00:41) correct 22% (00:46) wrong based on 36 sessions

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[GMAT math practice question]

When 2 fair dice are tossed, what is the probability that the difference between the 2 numbers that land face up will be 3?

A. $$\frac{1}{6}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D.$$\frac{2}{3}$$
E. $$\frac{5}{6}$$
[Reveal] Spoiler: OA

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Last edited by MathRevolution on 10 Dec 2017, 22:19, edited 1 time in total.

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Re: When 2 fair dice are tossed, what is the probability that the differen [#permalink]

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01 Dec 2017, 08:09
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MathRevolution wrote:
[GMAT math practice question]

10/ (probability) When 2 fair dice are tossed, what is the probability that the difference between the 2 numbers that land face up will be 3?

A. $$\frac{1}{6}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D.$$\frac{2}{3}$$
E. $$\frac{5}{6}$$

number of pairs that yield a difference of $$3$$ are {1,4}, {2,5}, {3,6}, {4,1}, {5,2}, {6,3} $$= 6$$

probability for getting any one pair for e.g {1,4} $$= \frac{1}{6}*\frac{1}{6}$$

since there are 6 such pairs, hence probability will be $$= \frac{1}{6}*\frac{1}{6}*6 =\frac{1}{6}$$

Option A

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Math Revolution GMAT Instructor
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Re: When 2 fair dice are tossed, what is the probability that the differen [#permalink]

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03 Dec 2017, 17:42
=>
6 pairs of numbers with this property can appear on the dice: (1,4), (4,1), (2,5), (5,2), (3,6) and (6,3). The total number of outcomes from rolling two dice is 36.
Thus, the probability that the two numbers will have a difference of 3 is $$\frac{6}{36} = \frac{1}{6}$$.

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Re: When 2 fair dice are tossed, what is the probability that the differen   [#permalink] 03 Dec 2017, 17:42
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