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When 2 fair dice are tossed, what is the probability that the differen

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 6398
GMAT 1: 760 Q51 V42
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When 2 fair dice are tossed, what is the probability that the differen  [#permalink]

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Updated on: 10 Dec 2017, 23:19
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15% (low)

Question Stats:

84% (01:17) correct 16% (01:23) wrong based on 60 sessions

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[GMAT math practice question]

When 2 fair dice are tossed, what is the probability that the difference between the 2 numbers that land face up will be 3?

A. $$\frac{1}{6}$$
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
D.$$\frac{2}{3}$$
E. $$\frac{5}{6}$$

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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $99 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Originally posted by MathRevolution on 01 Dec 2017, 01:13. Last edited by MathRevolution on 10 Dec 2017, 23:19, edited 1 time in total. PS Forum Moderator Joined: 25 Feb 2013 Posts: 1216 Location: India GPA: 3.82 Re: When 2 fair dice are tossed, what is the probability that the differen [#permalink] Show Tags 01 Dec 2017, 09:09 1 MathRevolution wrote: [GMAT math practice question] 10/ (probability) When 2 fair dice are tossed, what is the probability that the difference between the 2 numbers that land face up will be 3? A. $$\frac{1}{6}$$ B. $$\frac{1}{3}$$ C. $$\frac{1}{2}$$ D.$$\frac{2}{3}$$ E. $$\frac{5}{6}$$ number of pairs that yield a difference of $$3$$ are {1,4}, {2,5}, {3,6}, {4,1}, {5,2}, {6,3} $$= 6$$ probability for getting any one pair for e.g {1,4} $$= \frac{1}{6}*\frac{1}{6}$$ since there are 6 such pairs, hence probability will be $$= \frac{1}{6}*\frac{1}{6}*6 =\frac{1}{6}$$ Option A Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 6398 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: When 2 fair dice are tossed, what is the probability that the differen [#permalink] Show Tags 03 Dec 2017, 18:42 => 6 pairs of numbers with this property can appear on the dice: (1,4), (4,1), (2,5), (5,2), (3,6) and (6,3). The total number of outcomes from rolling two dice is 36. Thus, the probability that the two numbers will have a difference of 3 is $$\frac{6}{36} = \frac{1}{6}$$. Therefore, the answer is A. Answer : A _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Re: When 2 fair dice are tossed, what is the probability that the differen &nbs [#permalink] 03 Dec 2017, 18:42
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