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When 2 dices are tossed

As we are rolling 2 dice => Number of cases = \(6^2\) = 36

What is the probability that the difference between the 2 numbers that land face up will be 3?

Lets write down the possible cases
(1,4), (4,1)
(2,5), (5,2)
(3,6), (6,3)

=> 6 cases
=> P(difference of 2 faced numbers is 3) = \(\frac{6}{36}\) = \(\frac{1}{6}\)

So, Answer will be A
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

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