MathRevolution wrote:
[GMAT math practice question]
10/ (probability) When 2 fair dice are tossed, what is the probability that the difference between the 2 numbers that land face up will be 3?
A. \(\frac{1}{6}\)
B. \(\frac{1}{3}\)
C. \(\frac{1}{2}\)
D.\(\frac{2}{3}\)
E. \(\frac{5}{6}\)
number of pairs that yield a difference of \(3\) are {1,4}, {2,5}, {3,6}, {4,1}, {5,2}, {6,3} \(= 6\)
probability for getting any one pair for e.g {1,4} \(= \frac{1}{6}*\frac{1}{6}\)
since there are 6 such pairs, hence probability will be \(= \frac{1}{6}*\frac{1}{6}*6 =\frac{1}{6}\)
Option
A
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81% (00:42) correct 
