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Bunuel
Which of the following is the closest approximation to \([\sqrt{73} * \sqrt{239}] ÷ [\sqrt{7.2} + \sqrt{15.7}]\)?

A. 10
B. 15
C. 20
D. 25
E. 30


√73 is about 8.5.

√239 is about 15.5.

√7.2 is about 3.

√15.7 is about 4.

15.5 x 8.5 = 131.75 or about 130

3 + 4 = 7

Thus,

130/7 is about 20.

Answer: C
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Bunuel
Which of the following is the closest approximation to \([\sqrt{73} * \sqrt{239}] ÷ [\sqrt{7.2} + \sqrt{15.7}]\)?

A. 10
B. 15
C. 20
D. 25
E. 30

I calculated the lowest and highest possible values of the expressions.
Lowest means (8*15)/(2+3) and highest means (9*16)/(3+4). The results are 24 and 20.XX. So the closest approximation is 20.

P.S: 25 cannot be the answer as the max value is 24 so C it is
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IMO C

73 taken as 72 ( square root )= 8
239 taken as 225 = 15

7.2 taken as 4 = 2
15.7 taken as 16 = 4

= 8*15 / 2 + 4
= 8 * 15 / 6
= 20
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Bunuel
Which of the following is the closest approximation to \([\sqrt{73} * \sqrt{239}] ÷ [\sqrt{7.2} + \sqrt{15.7}]\)?

A. 10
B. 15
C. 20
D. 25
E. 30

We have: √73 ∗ √239 ≈ √81 ∗ √225 = 9 ∗ 15 = 135
Note that 73 was increased to 81 and 239 decreased to 225, this kind of compensates each other

Again: √7.2 + √15.7 ≈ √8 + √16 = 2√2 + 4 = 2 ∗ 1.4 + 4 = 6.8 ≈ 7

Thus: \([\sqrt{73} * \sqrt{239}] ÷ [\sqrt{7.2} + \sqrt{15.7}]\)
= 135 ÷ 7
= 19.3

Closest option is Option C
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