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Which of the following procedures is always equivalent to

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Director
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Which of the following procedures is always equivalent to [#permalink]

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New post 27 Feb 2007, 10:58
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Which of the following procedures is always equivalent to adding 5 given numbers and then dividing the sum by 5 ?

I. Multiplying the 5 numbers and then finding the 5th root of the product.

II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.

III. Ordering the 5 numbers numerically and then selecting the middle number

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

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Director
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Re: PS [#permalink]

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New post 27 Feb 2007, 11:22
SimaQ wrote:
Which of the following procedures is always equivalent to adding 5 given numbers and then dividing the sum by 5 ?

I. Multiplying the 5 numbers and then finding the 5th root of the product.

II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.

III. Ordering the 5 numbers numerically and then selecting the middle number

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III



II only . My answer is C

Ex : 2, 4, 6, 7,11

sum = 30
doubling the sum = 60
moving the decimal to left gives value 6

Adding five numbers and divide the sum by 5 is equivalent to C

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Senior Manager
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 [#permalink]

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New post 27 Feb 2007, 11:25
My ans is c

Basically, the q asks for average of 5 nos

Total/5 is the same as 2total/10. Moving the decimal one place to the left is dividing by 10.

We know that II is right, we have no other ans choice that combines with II. So I and III needs no checking.

I think, GMAT questions do not have such choices.

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Manager
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 [#permalink]

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New post 27 Feb 2007, 11:26
I get C

Use random numbers to disprove I
I used 1,12,26,54,125 = 218 / 5 = 43.6
Multiplying and taking 5th root is 18.something

C clearly doesnt work and the median and mean dont have to be the same

B worked for a bunch of sets of numbers including negatives
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CEO
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Re: PS [#permalink]

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New post 01 Jun 2007, 20:22
SimaQ wrote:
Which of the following procedures is always equivalent to adding 5 given numbers and then dividing the sum by 5 ?

I. Multiplying the 5 numbers and then finding the 5th root of the product.

II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.

III. Ordering the 5 numbers numerically and then selecting the middle number

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III


best way to solve this is to use easy (small), random, repeating numbers and divisible by 5.

1 + 2 + 1 + 2 + 4 = 10 / 5 = 2

only C answers this question.

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Re: Which of the following procedures is always equivalent to [#permalink]

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New post 03 Nov 2017, 03:39
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Re: Which of the following procedures is always equivalent to   [#permalink] 03 Nov 2017, 03:39
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