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# Which of the following procedures is always equivalent to

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Director
Joined: 06 Feb 2006
Posts: 881
Which of the following procedures is always equivalent to  [#permalink]

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27 Feb 2007, 11:58
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Which of the following procedures is always equivalent to adding 5 given numbers and then dividing the sum by 5 ?

I. Multiplying the 5 numbers and then finding the 5th root of the product.

II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.

III. Ordering the 5 numbers numerically and then selecting the middle number

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

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Director
Joined: 17 Jul 2006
Posts: 657

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27 Feb 2007, 12:22
SimaQ wrote:
Which of the following procedures is always equivalent to adding 5 given numbers and then dividing the sum by 5 ?

I. Multiplying the 5 numbers and then finding the 5th root of the product.

II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.

III. Ordering the 5 numbers numerically and then selecting the middle number

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

II only . My answer is C

Ex : 2, 4, 6, 7,11

sum = 30
doubling the sum = 60
moving the decimal to left gives value 6

Adding five numbers and divide the sum by 5 is equivalent to C
Senior Manager
Joined: 24 Oct 2006
Posts: 337

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27 Feb 2007, 12:25
My ans is c

Basically, the q asks for average of 5 nos

Total/5 is the same as 2total/10. Moving the decimal one place to the left is dividing by 10.

We know that II is right, we have no other ans choice that combines with II. So I and III needs no checking.

I think, GMAT questions do not have such choices.
Manager
Joined: 04 Oct 2006
Posts: 185

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27 Feb 2007, 12:26
I get C

Use random numbers to disprove I
I used 1,12,26,54,125 = 218 / 5 = 43.6
Multiplying and taking 5th root is 18.something

C clearly doesnt work and the median and mean dont have to be the same

B worked for a bunch of sets of numbers including negatives
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Joined: 21 Jan 2007
Posts: 2685
Location: New York City

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01 Jun 2007, 21:22
SimaQ wrote:
Which of the following procedures is always equivalent to adding 5 given numbers and then dividing the sum by 5 ?

I. Multiplying the 5 numbers and then finding the 5th root of the product.

II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.

III. Ordering the 5 numbers numerically and then selecting the middle number

(A) None
(B) I only
(C) II only
(D) III only
(E) I and III

best way to solve this is to use easy (small), random, repeating numbers and divisible by 5.

1 + 2 + 1 + 2 + 4 = 10 / 5 = 2

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Re: Which of the following procedures is always equivalent to  [#permalink]

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03 Nov 2017, 04:39
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Re: Which of the following procedures is always equivalent to &nbs [#permalink] 03 Nov 2017, 04:39
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