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X=5a+4
X=23b+7

5a has to be divisible by 5 and total has to be less than 100, so a must have to be less than 20. Take a=19, that will give u value of X=99.
Now check second equation. Divide 99 by 23 and u will find a remainder of 7. As (23*4=92). So 99 works.

So ans is 99.
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Bunuel
x is a positive integer less than 100. When x is divided by 5, the remainder is 4, and when x is divided by 23, the remainder is 7. What is the value of x?


A. 7
B. 30
C. 53
D. 76
E. 99

Take multiples of 23 & keep adding 7 to the number (<100). For every such number check if it's ending with 4 or 9.
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Only option when divided by 5 gives remainder 4 is 99, hence it is the answer choice

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Bunuel
x is a positive integer less than 100. When x is divided by 5, the remainder is 4, and when x is divided by 23, the remainder is 7. What is the value of x?


A. 7
B. 30
C. 53
D. 76
E. 99

Use options.

Only option E, which is 99, gives us remainder 4 when divided by 5. NO need to check anything else.

Answer E
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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