\(\frac{1}{2} +\frac{\frac{2}{3} *\frac{3}{8}}{4} - \frac{9}{16} =\frac{1}{2}+\frac{1}{16}-\frac{9}{16}=\frac{8}{16}+\frac{1}{16}-\frac{9}{16}=0\).

Answer: E.
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We need to simplify the expression using PEMDAS.

Parentheses
Exponents
Multiplication and Division
Addition and Subtraction

The calculation of an equation or expression must be carried out in the following order:

1) Operations within parentheses (or absolute value bars or radicals)
2) Exponents
3) Multiplication and division from left to right
4) Addition and subtraction from left to right



The answer is E.
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Neither of those violates any rule and both are correct:

\(\frac{1}{2}+\frac{1}{16}-\frac{9}{16}\)

You can treat it as \((\frac{1}{2}+\frac{1}{16})-\frac{9}{16}\) or \(\frac{1}{2}+(\frac{1}{16}-\frac{9}{16})\) or \((\frac{1}{2}-\frac{9}{16})+\frac{1}{16}\). This is because of commutative law, which says that any finite sum (or product) is unaltered by reordering its terms or factors. Simply put a + b = b + a and ab = ba.

Of course yo can simply transform all fractions having the same common denominator and proceed: \(\frac{8+1-9}{16}\).

Check for more HERE.

Hope it helps.
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Can someone help me understand why [(2/3 * 3/8)/4] doesn't equal 1? I multiplied the fractions in the numerator, and then multiplied them by the reciprocal of 1/4. Clearly that is incorrect, but I thought that was how dividing fractions worked.