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1/2 + [(2/3 * 3/8)/4] - 9/16 =

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1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 07 Dec 2012, 06:03
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\(\frac{1}{2} +\frac{\frac{2}{3} *\frac{3}{8}}{4} - \frac{9}{16}\).

(A) 29/16
(B) 19/16
(C) 15/16
(D) 9/13
(E) 0
[Reveal] Spoiler: OA

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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 18 Dec 2012, 23:28
I love it when you get 0 in the GMAT.

\(1/2 + (2/3)(3/8)(1/4) - 9/16 = 1/2 - 1/16 - 9/16 = 1/2 - 8/16 = 1/2-1/2=0\)

Answer: E
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 09 Jun 2016, 14:01
Walkabout wrote:
1/2 + [(2/3 * 3/8)/4] - 9/16 =

(A) 29/16
(B) 19/16
(C) 15/16
(D) 9/13
(E) 0


We need to simplify the expression using PEMDAS.

Parentheses
Exponents
Multiplication and Division
Addition and Subtraction

The calculation of an equation or expression must be carried out in the following order:

1) Operations within parentheses (or absolute value bars or radicals)
2) Exponents
3) Multiplication and division from left to right
4) Addition and subtraction from left to right

Image

The answer is E.
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 12 Jun 2017, 09:56
Hello from the GMAT Club BumpBot!

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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 21 Sep 2017, 22:46
Bunuel what difference does it make if we do not follow PEMDAS rule for addition?

For example:
1/2+1/16-9/16
= 1/2-8/16
=0


Or

1/2+1/16-9/16
= (8+1-9)/16
=Still 0
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 21 Sep 2017, 23:29
Shiv2016 wrote:
Bunuel what difference does it make if we do not follow PEMDAS rule for addition?

For example:
1/2+1/16-9/16
= 1/2-8/16
=0


Or

1/2+1/16-9/16
= (8+1-9)/16
=Still 0


Neither of those violates any rule and both are correct:

\(\frac{1}{2}+\frac{1}{16}-\frac{9}{16}\)

You can treat it as \((\frac{1}{2}+\frac{1}{16})-\frac{9}{16}\) or \(\frac{1}{2}+(\frac{1}{16}-\frac{9}{16})\) or \((\frac{1}{2}-\frac{9}{16})+\frac{1}{16}\). This is because of commutative law, which says that any finite sum (or product) is unaltered by reordering its terms or factors. Simply put a + b = b + a and ab = ba.

Of course yo can simply transform all fractions having the same common denominator and proceed: \(\frac{8+1-9}{16}\).

Check for more HERE.

Hope it helps.
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 =   [#permalink] 21 Sep 2017, 23:29
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