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1/2 + [(2/3 * 3/8)/4] - 9/16 =

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Joined: 02 Dec 2012
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1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 07 Dec 2012, 06:03
1
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A
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E

Difficulty:

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Question Stats:

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\(\frac{1}{2} +\frac{\frac{2}{3} *\frac{3}{8}}{4} - \frac{9}{16}\).

(A) 29/16
(B) 19/16
(C) 15/16
(D) 9/13
(E) 0
Spoiler: OA
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 07 Dec 2012, 06:08
Walkabout wrote:
1/2 + [(2/3 * 3/8)/4] - 9/16 =

(A) 29/16
(B) 19/16
(C) 15/16
(D) 9/13
(E) 0


\(\frac{1}{2} +\frac{\frac{2}{3} *\frac{3}{8}}{4} - \frac{9}{16} =\frac{1}{2}+\frac{1}{16}-\frac{9}{16}=\frac{8}{16}+\frac{1}{16}-\frac{9}{16}=0\).

Answer: E.
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 18 Dec 2012, 23:28
I love it when you get 0 in the GMAT.

\(1/2 + (2/3)(3/8)(1/4) - 9/16 = 1/2 - 1/16 - 9/16 = 1/2 - 8/16 = 1/2-1/2=0\)

Answer: E
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 09 Jun 2016, 14:01
2
Walkabout wrote:
1/2 + [(2/3 * 3/8)/4] - 9/16 =

(A) 29/16
(B) 19/16
(C) 15/16
(D) 9/13
(E) 0


We need to simplify the expression using PEMDAS.

Parentheses
Exponents
Multiplication and Division
Addition and Subtraction

The calculation of an equation or expression must be carried out in the following order:

1) Operations within parentheses (or absolute value bars or radicals)
2) Exponents
3) Multiplication and division from left to right
4) Addition and subtraction from left to right

Image

The answer is E.
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 21 Sep 2017, 22:46
Bunuel what difference does it make if we do not follow PEMDAS rule for addition?

For example:
1/2+1/16-9/16
= 1/2-8/16
=0


Or

1/2+1/16-9/16
= (8+1-9)/16
=Still 0
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 = [#permalink]

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New post 21 Sep 2017, 23:29
Shiv2016 wrote:
Bunuel what difference does it make if we do not follow PEMDAS rule for addition?

For example:
1/2+1/16-9/16
= 1/2-8/16
=0


Or

1/2+1/16-9/16
= (8+1-9)/16
=Still 0


Neither of those violates any rule and both are correct:

\(\frac{1}{2}+\frac{1}{16}-\frac{9}{16}\)

You can treat it as \((\frac{1}{2}+\frac{1}{16})-\frac{9}{16}\) or \(\frac{1}{2}+(\frac{1}{16}-\frac{9}{16})\) or \((\frac{1}{2}-\frac{9}{16})+\frac{1}{16}\). This is because of commutative law, which says that any finite sum (or product) is unaltered by reordering its terms or factors. Simply put a + b = b + a and ab = ba.

Of course yo can simply transform all fractions having the same common denominator and proceed: \(\frac{8+1-9}{16}\).

Check for more HERE.

Hope it helps.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
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Re: 1/2 + [(2/3 * 3/8)/4] - 9/16 =   [#permalink] 21 Sep 2017, 23:29
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