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Sub 505 (Easy)|   Algebra|   Arithmetic|                           
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(1+\sqrt{5})(1-\sqrt{5})=

(A) -4
(B) 2
(C) 6
(D) -4-2\sqrt{5}
(E) 6-2\sqrt{5}

Sol: We know a^2-b^2= (a-b)(a+b).

Therefore the above can be re-written as (1^2-\sqrt{5}^2)------>(1-5)= -4 Ans A
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We need to find the value of \((1+\sqrt{5})(1-\sqrt{5})\)

Given expression is of the form (a+b)*(a-b) where
  • 1 = a
  • \(\sqrt{5}\) = b
And and we know that (a+b)*(a-b) = \(a^2 - b^2\)

=> \((1+\sqrt{5})(1-\sqrt{5})\) = \(1^2 - \sqrt{5}^2\) = 1 - 5 = -4

So, Answer will be A
Hope it helps!­

Watch the following video to MASTER Roots

­
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Bunuel
\((1+\sqrt{5})(1-\sqrt{5})=\)

(A) -4
(B) 2
(C) 6
(D) \(-4-2\sqrt{5}\)
(E) \(6-2\sqrt{5}\)





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

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