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wanna_mba_2005
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wanna_mba_2005
(3)7 different objects must be divided among 3 people.In how many ways can this be done if at least one of them gets exactly one object?
(a)2484 (b)1176 (c)729 (d)None of these


# of combs where all three get exactly 1 object is 0.

# of combs where 2 get exactly 1 object is 3*2*C[2,7].

# of combs where 1 gets exactly 1 object is 3*7*(2^6 - 6).

=> total # = 6*7*6/2 + 3*7*58 = 7*(18 + 174) = 192*7 = 1344.

None of the answers... Maybe it is reasonable to notice that 7 should divide the answer. 2484 does not satisfy, 729 either. But 1176 = 24*(50-1) :: 7...
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Thanks to all of you for solving the problems.The third one still continues to nag me.The official answer happens to be (b) and I am clueless...just one of those things you can sleep over!
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The answer is 2187.

"One or two of them can get no objects" means objects can be distributed in any way, that is the first person can either get an object or not, the 2nd person can either get an object or not, and the 3rd person can either get an object or not. The task is the same as if we were simply asked t calculate the number of ways in which 3 objects can be distributed among 7 people and each person should not necessarily get an object.

Thus, the number of ways is 3^7=2187
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Hello from the GMAT Club BumpBot!

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