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24 Jun 2004, 11:07
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(1)7 different objects must be divided among 3 people.In how many ways can this be done if one or tow of them can get no objects?
(a)15120 (b)2187 (c)3003 (d)792
(2)7 different objects must be divided among 3 people.In how many ways can this be done if at least one out of them must get no objects?
(a)381 (b)36 (c)84 (d)174
(3)7 different objects must be divided among 3 people.In how many ways can this be done if at least one of them gets exactly one object?
(a)2484 (b)1176 (c)729 (d)None of these
(a)15120 (b)2187 (c)3003 (d)792
(2)7 different objects must be divided among 3 people.In how many ways can this be done if at least one out of them must get no objects?
(a)381 (b)36 (c)84 (d)174
(3)7 different objects must be divided among 3 people.In how many ways can this be done if at least one of them gets exactly one object?
(a)2484 (b)1176 (c)729 (d)None of these
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25 Jun 2004, 00:12
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hello wannabe
welcome to gmatclub. you will have a better response if you post one question per thread.
welcome to gmatclub. you will have a better response if you post one question per thread.
25 Jun 2004, 00:50
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wanna_mba_2005
1. In 3^7 = 2187 ways, because each object can go to 3 different people, and by the rule of multiplying we get 3*3*...*3 = 3^7 ways.
2. If first has no objects, then 2^7. => 3*2^7 - (common cases, when at least 2 get no objects, there are 3 such cases) = 128*3 - 3 = 381.
