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22 Jan 2005, 03:53
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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1/ Is x > y?
(1) (x+y)/2 > 0
(2) (y-x)(y+x) > 0
2/ One hundred students are taking both law and accounting. how many students are taking only accounting?
(1) 180 students are taking EITHER law OR accounting.
(2) 50 students are taking law but not accounting.
Directions:
A. If statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked;
B. If statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked;
C. If BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient;
D. If EACH statement ALONE is sufficient to answer the question asked;
E. If statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.
(1) (x+y)/2 > 0
(2) (y-x)(y+x) > 0
2/ One hundred students are taking both law and accounting. how many students are taking only accounting?
(1) 180 students are taking EITHER law OR accounting.
(2) 50 students are taking law but not accounting.
Directions:
A. If statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked;
B. If statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked;
C. If BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient;
D. If EACH statement ALONE is sufficient to answer the question asked;
E. If statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.
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Thank you for understanding, and happy exploring!
22 Jan 2005, 05:18
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Many thanks, HSWKM!
However, for question no. 1, my choice is C.
(2) (y-x)(y+x) > 0
=> (y-x > 0) AND (y+x > 0)
OR (y-x < 0) AND (y+x < 0)
From (1) (x+y)/2 > 0 => x+y > 0
From (1) & (2) => y-x > 0 <=> y > x.
So BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient
For question no. 2, please could you give your solution also?
Many thanks again.
However, for question no. 1, my choice is C.
(2) (y-x)(y+x) > 0
=> (y-x > 0) AND (y+x > 0)
OR (y-x < 0) AND (y+x < 0)
From (1) (x+y)/2 > 0 => x+y > 0
From (1) & (2) => y-x > 0 <=> y > x.
So BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient
For question no. 2, please could you give your solution also?
Many thanks again.
22 Jan 2005, 07:14
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C, C
For the second one---
1) gives us 180 = L + A
so we know L (U) A = 180 +100 = 280
not sufficient to know what is A
leaves us with choices B,C and E
2) gives us L= 50
if used alone
we won't be able to find [L (U) A] and [A] in tghe equation-
[L (U) A] = [L] + [A] + [L (I) A]
[L (U) A] = 50 + [A] + 100
not sufficient to know [A]...
but combining 1) and 2) gives us 50 + A = 180
i.e. A = 130
For the second one---
1) gives us 180 = L + A
so we know L (U) A = 180 +100 = 280
not sufficient to know what is A
leaves us with choices B,C and E
2) gives us L= 50
if used alone
we won't be able to find [L (U) A] and [A] in tghe equation-
[L (U) A] = [L] + [A] + [L (I) A]
[L (U) A] = 50 + [A] + 100
not sufficient to know [A]...
but combining 1) and 2) gives us 50 + A = 180
i.e. A = 130
