Bunuel wrote:
10! + 9! can be rewritten as:
A. 9!(10)
B. 11!/10
C. (10!)^2*9
D. (9!)^2 + 10
E. 19!
First recognize that 10! = (10)(9!)
Here's why:
10! = (10)
(9)(8)(7)(6)(5)(4)(3)(2)(1)= (10)
(9!)So....
10! + 9! = (10)(9!) + 9!
= 9!(10 + 1)
[I factored out the 9!]= 9!(11)
Check the answer choice.....9!(11) isn't there! So, we'll need to check each answer choice to see which one can be expressed as (9!)(11)
A. 9!(10)
We can clearly see that this is not equal to (9!)(11)
ELIMINATE A
B. 11!/10
11!/10 = (11)(
10)(9)(8)(7)(6)(5)(4)(3)(2)(1)/(
10)
= (11)
(9)(8)(7)(6)(5)(4)(3)(2)(1)= (11)
(9!) PERFECT!!
= B
Cheers,
Brent
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69% (01:25) correct 
