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Bunuel
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3^5= 243

10^15= 100.....

Now, 100....-243= 999..757

So, sum= 9+9+9...+7+5+7= 9*something + 19

Subtracting 19 from each answer choice to check whether the remainder is divisible by 9.

A) 225-19= 206; no
B) 234-19= 215; no
C) 243-19= 224; no
D) 262-19= 243; yes
E) 272-19= 253; no

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Easiest approach in my opinion: (max 40sec)

100^15=10^30

-> a 1 with 30 zeroes

If you deduct 3^5=243 from a 1 with 30 zeroes

You will have 27 times 9 and 757 as the last three digits

27x9 + 7 + 5+ 7 = 30 x 9 - 3 x 9 + 19 = 270 -27 + 19 = 270 - 8 = 262 -> Option D
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Lets simplify:

100^15 - 3^5 =?
10^30 - 3^5 = ?

We know 3^5 = 243

To understand, lets take smaller difference:
10^3 - 3^5 = 757
10^4 - 3^5 = 9757 (when there is 10^4, there is one 9 in the difference)
10^5 - 3^5 = 99757 (when there is 10^5, there are two 9's in the difference)
10^6 - 3^5 = 999757 (when there is 10^6, there are three 9's in the difference)

hence,
10^30 - 3^5 = 99....99757 (when there is 10^30, there twenty seven 9's in the difference)
total sum of the digits = 9*27 + 7 + 5 + 7 = 262

D is correct

Want to give a Free GMAT diagnostic test: https://2ly.link/2Alsw

Bunuel
\(100^{15}-3^5\) is written as an integer. What is the sum of the digits of this integer?

A. 225
B. 234
C. 243
D. 262
E. 272
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