Last visit was: 21 Apr 2026, 14:16 It is currently 21 Apr 2026, 14:16
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Googlore
Joined: 11 Sep 2006
Last visit: 21 Mar 2007
Posts: 26
Own Kudos:
21
 [18]
Posts: 26
Kudos: 21
 [18]
Kudos
Add Kudos
18
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,728
Own Kudos:
810,460
 [4]
Given Kudos: 105,800
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,728
Kudos: 810,460
 [4]
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 21 Apr 2026
Posts: 22,276
Own Kudos:
26,526
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,276
Kudos: 26,526
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
BrentGMATPrepNow
User avatar
Major Poster
Joined: 12 Sep 2015
Last visit: 31 Oct 2025
Posts: 6,733
Own Kudos:
36,440
 [1]
Given Kudos: 799
Location: Canada
Expert
Expert reply
Posts: 6,733
Kudos: 36,440
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Googlore
\(\frac{1001^2-999^2}{101^2-99^2}=\)

A. 10
B. 20
C. 40
D. 80
E. 100


Key Property: \(x^2 - y^2 = (x+y)(x-y)\) (i.e., factoring a difference of squares)

\(\frac{1001^2-999^2}{101^2-99^2}=\frac{(1001+999)(1001-999)}{(101+999)(101-99)}\)

\(=\frac{(2000)(2)}{(200)(2)}\)

\(=\frac{4000}{400}\)

\(= 10\)

Answer: A
User avatar
totaltestprepNick
Joined: 25 Aug 2014
Last visit: 21 Apr 2026
Posts: 469
Own Kudos:
Given Kudos: 2
GMAT 1: 750 Q49 V42
GMAT 1: 750 Q49 V42
Posts: 469
Kudos: 4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Googlore
\(\frac{1001^2-999^2}{101^2-99^2}=\)

A. 10
B. 20
C. 40
D. 80
E. 100





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

[email protected]
Moderators:
Math Expert
109728 posts
Tuck School Moderator
853 posts