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19 Dec 2025, 07:32
Kudos
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Statement 1: #boxes weighing 5 pounds = 2 * #boxes weighing 11 pounds
=> Average weight of box = [5(2x) + 11x + 7y] / (2x + x + y) where x is #boxes weighing 11 pounds. This doesn't give us any definite answer. Thus, Statement 1 is insufficient.
Statement 2: Average weight of box = [5(4) + 7(2) + 11(2)] / (4 + 2 + 2) = 7 pounds. THus, statement 2 is sufficient.
Hence, Answer is B.
=> Average weight of box = [5(2x) + 11x + 7y] / (2x + x + y) where x is #boxes weighing 11 pounds. This doesn't give us any definite answer. Thus, Statement 1 is insufficient.
Statement 2: Average weight of box = [5(4) + 7(2) + 11(2)] / (4 + 2 + 2) = 7 pounds. THus, statement 2 is sufficient.
Hence, Answer is B.
19 Dec 2025, 07:40
Kudos
Bookmarks
Bunuel
We have either 5,7, or 11 pounds shipment
Average here is : total weight / total shipment
Statement 1 : so number of 5 pounds shipment is double as compared to 11 pound
so let's check with 10 - 5 pound shipment + 5 - 11 pound shipment
10 * 5 + 5 *11 =105
105/ 15 = 7 ( here we don't the shipment number of 7 pound shipment and tbh it doesn't matter because already the average is 7 )
We can check with other 2:1 ratio too, we will get the average of 7 ----- Sufficient
Statement 2 : here we have the ratio 4k : 2k : 2k
So Average here will be 56k/8k = 7 ----- sufficient
Our answer here is D
19 Dec 2025, 07:42
Kudos
Bookmarks
total weight: 5X + 7Y + 11Z
total number of boxes: X + Y + Z
(1)
X=2Z
total weight: 10Z + 7Y + 11Z = 21Z + 7Y = 7(3Z + Y)
total number of boxes: 2Z + Y + Z = 3Z + Y
average = 7
Condition (1) is sufficient
(2)
X=2Z
Y=Z
total weight: 10Z + 7Z + 11Z = 28Z
total number of boxes: 2Z + Z + Z = 4Z
average = 7
Condition (2) is sufficient
The answer is D
total number of boxes: X + Y + Z
(1)
X=2Z
total weight: 10Z + 7Y + 11Z = 21Z + 7Y = 7(3Z + Y)
total number of boxes: 2Z + Y + Z = 3Z + Y
average = 7
Condition (1) is sufficient
(2)
X=2Z
Y=Z
total weight: 10Z + 7Z + 11Z = 28Z
total number of boxes: 2Z + Z + Z = 4Z
average = 7
Condition (2) is sufficient
The answer is D
