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24 Dec 2025, 08:05
Kudos
Bookmarks
This is an arithmetic progression with first term=1, common difference=0.5
The fines will go on like 1 1.5 2 2.5 3 3.5...
Sum of this series = (n/2)*(2*1+(n-1)*0.5)
= n(0.25n+0.75)
Trying the answer choices
n = 4, sum = 4(1+0.75) = 7 - not available
n = 5, sum = 5(1.25+0.75) = 10 available
So, number of overdue days = 5
total fine = 10
The fines will go on like 1 1.5 2 2.5 3 3.5...
Sum of this series = (n/2)*(2*1+(n-1)*0.5)
= n(0.25n+0.75)
Trying the answer choices
n = 4, sum = 4(1+0.75) = 7 - not available
n = 5, sum = 5(1.25+0.75) = 10 available
So, number of overdue days = 5
total fine = 10
Bunuel
24 Dec 2025, 08:14
Kudos
Bookmarks
First day fine = $1
Each day increase = $0.5
Hence the fines would be $1, $1.5, $2, $2.5....
This is an AP
where a = 1 and d = 0.5
=> Sum of first n terms = n/2 * (2a +(n-1)*d) = n/2*(2+(n-1)0.5) = n/2 * (0.5n + 1.5) = 0.25n^2 + 0.75n
Hence using the values given for n we get
n = 4
Sum = 0.25(16) + 0.75(4) = 7
n = 5
Sum = 0.25(25) + 0.75(5) = 10
This works
Number of overdue days (n) = 5
Fine (Sum) = 10
Each day increase = $0.5
Hence the fines would be $1, $1.5, $2, $2.5....
This is an AP
where a = 1 and d = 0.5
=> Sum of first n terms = n/2 * (2a +(n-1)*d) = n/2*(2+(n-1)0.5) = n/2 * (0.5n + 1.5) = 0.25n^2 + 0.75n
Hence using the values given for n we get
n = 4
Sum = 0.25(16) + 0.75(4) = 7
n = 5
Sum = 0.25(25) + 0.75(5) = 10
This works
Number of overdue days (n) = 5
Fine (Sum) = 10
Bunuel
24 Dec 2025, 08:20
Kudos
Bookmarks
Calculate total fine:
1 overdue day, fine 1, total fine 1
2 overdue day, fine 1.5, total fine 2.5
3 overdue day, fine 2, total fine 4.5
4 overdue day, fine 2.5, total fine 7
5 overdue day, fine 3, total fine 10, that fits in the possible options
Number of overdue days=5
Total fine=10
1 overdue day, fine 1, total fine 1
2 overdue day, fine 1.5, total fine 2.5
3 overdue day, fine 2, total fine 4.5
4 overdue day, fine 2.5, total fine 7
5 overdue day, fine 3, total fine 10, that fits in the possible options
Number of overdue days=5
Total fine=10
