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120 tickets are to be evenly distributed to n people. If n is greater

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Math Revolution GMAT Instructor
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120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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New post Updated on: 21 Dec 2018, 10:02
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

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[Math Revolution GMAT math practice question]

\(120\) tickets are to be evenly distributed to \(n\) people. If \(n\) is greater than \(1\) and the number of tickets given to each person is greater than \(1\), what is the greatest possible value of \(n\)?

\(A. 9\)
\(B. 10\)
\(C. 12\)
\(D. 14\)
\(E. 15\)

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Originally posted by MathRevolution on 20 Dec 2018, 02:01.
Last edited by MathRevolution on 21 Dec 2018, 10:02, edited 3 times in total.
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Re: 120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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New post 20 Dec 2018, 03:43
MathRevolution wrote:
[Math Revolution GMAT math practice question]

\(120\) tickets are to be evenly distributed to \(n\) people. If \(n\) is greater than \(1\) and the number of tickets given to each person is greater than \(1\), what is the greatest possible value of \(n\)?

\(A. 9\)
\(B. 10\)
\(C. 12\)
\(D. 14\)
\(E. 15\)




Please check OA MathRevolution.

120 is not even divisible by 14.
SO every person will not get same (evenly distributed) chocolates.
IMO
Ans should be E.
15 people
each person gets 8 chocolates
total= 15*8= 120

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Nitesh
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Re: 120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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New post 20 Dec 2018, 04:39
Ans is E.. Must be an error in OA
Math Revolution GMAT Instructor
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Re: 120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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New post 23 Dec 2018, 19:22
=>

\(120 = 2^3*3^1*5^1\) or \(120 = 8*15.\)
Thus \(15\) is the greatest factor among choices.

Therefore, the answer is E.
Answer: E
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Re: 120 tickets are to be evenly distributed to n people. If n is greater   [#permalink] 23 Dec 2018, 19:22
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