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Math Revolution GMAT Instructor V
Joined: 16 Aug 2015
Posts: 7631
GMAT 1: 760 Q51 V42 GPA: 3.82
120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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Difficulty:   15% (low)

Question Stats: 93% (01:21) correct 7% (01:30) wrong based on 75 sessions

### HideShow timer Statistics [Math Revolution GMAT math practice question]

$$120$$ tickets are to be evenly distributed to $$n$$ people. If $$n$$ is greater than $$1$$ and the number of tickets given to each person is greater than $$1$$, what is the greatest possible value of $$n$$?

$$A. 9$$
$$B. 10$$
$$C. 12$$
$$D. 14$$
$$E. 15$$

_________________

Originally posted by MathRevolution on 20 Dec 2018, 02:01.
Last edited by MathRevolution on 21 Dec 2018, 10:02, edited 3 times in total.
Manager  S
Joined: 04 Jun 2018
Posts: 157
GMAT 1: 610 Q48 V25 GMAT 2: 690 Q50 V32 GMAT 3: 710 Q50 V36 Re: 120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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MathRevolution wrote:
[Math Revolution GMAT math practice question]

$$120$$ tickets are to be evenly distributed to $$n$$ people. If $$n$$ is greater than $$1$$ and the number of tickets given to each person is greater than $$1$$, what is the greatest possible value of $$n$$?

$$A. 9$$
$$B. 10$$
$$C. 12$$
$$D. 14$$
$$E. 15$$

120 is not even divisible by 14.
SO every person will not get same (evenly distributed) chocolates.
IMO
Ans should be E.
15 people
each person gets 8 chocolates
total= 15*8= 120

Regards
Nitesh
Intern  B
Joined: 04 Apr 2017
Posts: 4
GMAT 1: 640 Q47 V31 Re: 120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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Ans is E.. Must be an error in OA
Math Revolution GMAT Instructor V
Joined: 16 Aug 2015
Posts: 7631
GMAT 1: 760 Q51 V42 GPA: 3.82
Re: 120 tickets are to be evenly distributed to n people. If n is greater  [#permalink]

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=>

$$120 = 2^3*3^1*5^1$$ or $$120 = 8*15.$$
Thus $$15$$ is the greatest factor among choices.

_________________ Re: 120 tickets are to be evenly distributed to n people. If n is greater   [#permalink] 23 Dec 2018, 19:22
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# 120 tickets are to be evenly distributed to n people. If n is greater  