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16 ounces of birdseed mix contains 10% sesame seed by weight. How much [#permalink]
Bunuel wrote:
16 ounces of birdseed mix contains 10% sesame seed by weight. How much sesame seed must be added to produce a mix that is 20% sesame seed by weight?

(A) 1 ounce
(B) 1.6 ounces
(C) 2 ounces
(D) 2.4 ounces
(E) 4 ounces



\(\frac{1.6}{16}=.10\)
\(\frac{1.6+x}{16+x}=.20\)
\(1.6+x = 3.2+.2x\)
\(.8x=1.6\)
\(x=2\)

Ans = C
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Re: 16 ounces of birdseed mix contains 10% sesame seed by weight. How much [#permalink]
Bunuel wrote:
16 ounces of birdseed mix contains 10% sesame seed by weight. How much sesame seed must be added to produce a mix that is 20% sesame seed by weight?

(A) 1 ounce
(B) 1.6 ounces
(C) 2 ounces
(D) 2.4 ounces
(E) 4 ounces


let x=ounces of sesame seed to be added
1.6+x=.2(16+x)
x=2 ounces
C
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16 ounces of birdseed mix contains 10% sesame seed by weight. How much [#permalink]
Bunuel wrote:
16 ounces of birdseed mix contains 10% sesame seed by weight. How much sesame seed must be added to produce a mix that is 20% sesame seed by weight?

(A) 1 ounce
(B) 1.6 ounces
(C) 2 ounces
(D) 2.4 ounces
(E) 4 ounces



let x ounces of sesame seed is added to get 20% mix

so BM1(birdseed mix) contains = 10% sesame seed

BM2 contains = 100% sesame seed

therefore 16/x = (10 - 20)/(20-100)

16/x = 1/8

x = 16/8

x = 2 ounces

this method takes much less time
this method is explained in Removal/Replacement in Mixtures
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Re: 16 ounces of birdseed mix contains 10% sesame seed by weight. How much [#permalink]
Question: 16 ounces of birdseed mix contains 10% sesame seed by weight. How much sesame seed must be added to produce a mix that is 20% sesame seed by weight?

Let x = sesame seed added

amount of sesame seed = 1.6 + m
amount of birdseed = 16 + m

1. 6 + m / 16 + m = 2/10

2(16 + x) = 16 + 10x
32 + 2x = 16 + 10x
16 = 8x
2 = x

Answer is C.
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Re: 16 ounces of birdseed mix contains 10% sesame seed by weight. How much [#permalink]
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Re: 16 ounces of birdseed mix contains 10% sesame seed by weight. How much [#permalink]
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