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05 Jun 2018, 22:06
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
75% (01:26) correct
25%
(01:32)
wrong
based on 240
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16 ounces of birdseed mix contains 10% sesame seed by weight. How much sesame seed must be added to produce a mix that is 20% sesame seed by weight?
(A) 1 ounce
(B) 1.6 ounces
(C) 2 ounces
(D) 2.4 ounces
(E) 4 ounces
(A) 1 ounce
(B) 1.6 ounces
(C) 2 ounces
(D) 2.4 ounces
(E) 4 ounces
05 Jun 2018, 22:18
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Solution
Given:
- • 16 ounces of birdseed mix contains 10% sesame seed by weight
To find:
- • What amount of sesame seed must be added to produce a mix that is 20% sesame seed by weight
Approach and Working:
- • In the initial mix, amount of sesame seed = 16 * 0.1 = 1.6 ounces
Let us assume that the amount of sesame seed to be mixed is m ounces
Therefore, after mixing,
- • The amount of sesame seed = 1.6 + m
• The total amount of mix = 16 + m
As the sesame seed accounts for 20% of the total mix amount, we can write
- • (16 + m) * 0.2 = 1.6 + m
Or, 3.2 + 0.2m = 1.6 + m
Or, 0.8m = 1.6
Or, m = 2
Hence, the correct answer is option C.
Answer: C
05 Jun 2018, 22:31
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16 ounces of birdseed mix contains 10% sesame seed by weight. How much sesame seed must be added to produce a mix that is 20% sesame seed by weight?
(A) 1 ounce
(B) 1.6 ounces
(C) 2 ounces
(D) 2.4 ounces
(E) 4 ounces
In 16 Ounces, we have 10% sesame seed i.e. 1.6 ounce.
now let assume x ounce of sesame seed needed to make mixture that contains 20% of sesame seed
=> (1.6+x)/(16+x)= 1/5
=> by cross-multiplication, 8+5x= 16+x
=> 4x=8
=> x=2
C is the answer.
(A) 1 ounce
(B) 1.6 ounces
(C) 2 ounces
(D) 2.4 ounces
(E) 4 ounces
In 16 Ounces, we have 10% sesame seed i.e. 1.6 ounce.
now let assume x ounce of sesame seed needed to make mixture that contains 20% of sesame seed
=> (1.6+x)/(16+x)= 1/5
=> by cross-multiplication, 8+5x= 16+x
=> 4x=8
=> x=2
C is the answer.
