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# (2^8 + 2^9)/3 =

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Math Expert
Joined: 02 Sep 2009
Posts: 54376

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08 Jul 2017, 05:57
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Difficulty:

5% (low)

Question Stats:

98% (00:37) correct 2% (02:33) wrong based on 77 sessions

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$$\frac{(2^8 + 2^9)}{3} =$$

A. $$(\frac{2}{3})^8$$

B. $$(1.5)^8$$

C. $$2^8$$

D. $$2^9$$

E. $$2^{10}$$

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Re: (2^8 + 2^9)/3 =  [#permalink]

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08 Jul 2017, 06:01
Bunuel wrote:
$$\frac{(2^8 + 2^9)}{3} =$$

A. $$(\frac{2}{3})^8$$

B. $$(1.5)^8$$

C. $$2^8$$

D. $$2^9$$

E. $$2^{10}$$

$$\frac{(2^8 + 2^9)}{3}$$

Taking $$2^8$$ common, we get;

$$\frac{2^8 (1 + 2)}{3}$$

$$\frac{2^8 *3}{3}$$

$$2^8$$

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Re: (2^8 + 2^9)/3 =  [#permalink]

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09 Jul 2017, 10:33
Take 2^8 common and out of bracket:

2^8 (1+2)/3

+1 kudos if u like the post.
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Joined: 19 Jan 2014
Posts: 35
Schools: Melbourne '20
GMAT 1: 670 Q45 V37
Re: (2^8 + 2^9)/3 =  [#permalink]

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09 Jul 2017, 10:37
(2^8+2^9)/(3) = 2^8(1+2^1)/(3) = 2^8(3)/(3) = 2^8

Option C.

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Re: (2^8 + 2^9)/3 =   [#permalink] 09 Jul 2017, 10:37
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# (2^8 + 2^9)/3 =

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