GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 17 Dec 2018, 04:10

R1 Decisions:

Michigan Ross Chat (US calls are expected today)  |  UCLA Anderson Chat  (Calls expected to start at 7am PST; Applicants from Asia will hear first)


Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in December
PrevNext
SuMoTuWeThFrSa
2526272829301
2345678
9101112131415
16171819202122
23242526272829
303112345
Open Detailed Calendar
  • 10 Keys to nail DS and CR questions

     December 17, 2018

     December 17, 2018

     06:00 PM PST

     07:00 PM PST

    Join our live webinar and learn how to approach Data Sufficiency and Critical Reasoning problems, how to identify the best way to solve each question and what most people do wrong.
  • R1 Admission Decisions: Estimated Decision Timelines and Chat Links for Major BSchools

     December 17, 2018

     December 17, 2018

     10:00 PM PST

     11:00 PM PST

    From Dec 5th onward, American programs will start releasing R1 decisions. Chat Rooms: We have also assigned chat rooms for every school so that applicants can stay in touch and exchange information/update during decision period.

(2^3^2 - (2^3)^2)/28 =

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 51259
(2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post 03 Aug 2018, 02:50
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

54% (00:56) correct 46% (00:40) wrong based on 61 sessions

HideShow timer Statistics

Manager
Manager
User avatar
S
Joined: 13 Feb 2018
Posts: 135
CAT Tests
(2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post 03 Aug 2018, 02:55
As math experts say begin from the top
\(\frac{2^9-2^9}{28}\)=0

IMO
Ans: A
SC Moderator
User avatar
P
Joined: 30 Jan 2015
Posts: 672
Location: India
Concentration: Operations, Marketing
GPA: 3.5
(2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post Updated on: 03 Aug 2018, 14:58
(2^3^2 - (2^3)^2) / 28
(2^9 - 2^6 ) / 28
2^6 * (2^3 - 1) / 4 * 7
2^6 * 7 / 4 * 7
64 / 4
16

Hence, E.
_________________

The few, the fearless !

Thanks :-)


Originally posted by sudarshan22 on 03 Aug 2018, 03:04.
Last edited by sudarshan22 on 03 Aug 2018, 14:58, edited 2 times in total.
Senior SC Moderator
avatar
V
Joined: 22 May 2016
Posts: 2218
Premium Member CAT Tests
(2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post 03 Aug 2018, 14:51
Bunuel wrote:
\(\frac{{2^3}^{2} - {(2^3)}^{2}}{28}\) =


A. 0

B. \(\frac{4}{7}\)

C. 8

D. 12

E. 16

Careful*: \({2^3}^{2}=(2)^{(3^2)}=2^9\)
On the other hand, \({(2^3)}^{2}=(2)^{(3*2)}=2^6\)

\(\frac{{2^3}^{2} - {(2^3)}^{2}}{28}\)

\(\frac{2^{9}-2^6}{2^2*7}\)

\(\frac{2^{6}(2^3-1)}{2^2*7}=\frac{2^6*7}{2^2*7}=\)

\(\frac{2^6}{2^2}=2^{(6-2)}=2^4=16\)

Answer
E


*\(a^{m^n}=a^{(m^n)}\) and not \((a^m)^n\). So the first term in the numerator is \(2^9\). The converse of the initial statement is also true. The second term in the prompt has one exponent inside and one exponent outside the parentheses. That placement of parentheses and exponents mimics this term: \((a^m)^n\) -- and not this term: \(a^{(m^n)}\) . The second term in the numerator, in other words, is \(2^6\). See Bunuel , here - scroll down to "Exponents."
Manager
Manager
avatar
B
Joined: 22 Sep 2017
Posts: 173
CAT Tests
Re: (2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post 06 Aug 2018, 22:26
sudarshan22 wrote:
(2^3^2 - (2^3)^2) / 28
(2^9 - 2^6 ) / 28
2^6 * (2^3 - 1) / 4 * 7
2^6 * 7 / 4 * 7
64 / 4
16

Hence, E.


Hello sudarshan22 Bunuel,
As per my knowledge both elements are same and answer should be A(0).
Could you please suggest any resource for my reference.
SC Moderator
User avatar
P
Joined: 30 Jan 2015
Posts: 672
Location: India
Concentration: Operations, Marketing
GPA: 3.5
Re: (2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post 06 Aug 2018, 23:57
jackspire wrote:
Hello sudarshan22 Bunuel,
As per my knowledge both elements are same and answer should be A(0).
Could you please suggest any resource for my reference.


jackspire
Answers to of your questions have been provided in the above post by generis, please check the post and all your doubts will be clear.
_________________

The few, the fearless !

Thanks :-)

Manager
Manager
avatar
B
Joined: 22 Sep 2017
Posts: 173
CAT Tests
Re: (2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post 07 Aug 2018, 02:41
sudarshan22 wrote:
jackspire wrote:
Hello sudarshan22 Bunuel,
As per my knowledge both elements are same and answer should be A(0).
Could you please suggest any resource for my reference.


jackspire
Answers to of your questions have been provided in the above post by generis, please check the post and all your doubts will be clear.


sudarshan22,
Yup. Missed it.
Thanks.
Senior Manager
Senior Manager
User avatar
D
Joined: 22 Feb 2018
Posts: 413
CAT Tests
Re: (2^3^2 - (2^3)^2)/28 =  [#permalink]

Show Tags

New post 07 Aug 2018, 02:58
Bunuel wrote:
\(\frac{{2^3}^{2} - {(2^3)}^{2}}{28}\) =


A. 0

B. \(\frac{4}{7}\)

C. 8

D. 12

E. 16

OA:E
\(\frac{{2^3}^{2} - {(2^3)}^{2}}{28}=\frac{{2^9 - 2^3*2^3}}{28}=\frac{{2^9 - 2^6}}{28}=\frac{2^6(2^3-1)}{28}=\frac{2^6*7}{2^2*7}=2^4=16\)
_________________

Good, good Let the kudos flow through you

GMAT Club Bot
Re: (2^3^2 - (2^3)^2)/28 = &nbs [#permalink] 07 Aug 2018, 02:58
Display posts from previous: Sort by

(2^3^2 - (2^3)^2)/28 =

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.