2 people are to be selected from Abraham, Benjamin, Chris, and Dave.

Question

2 people are to be selected from Abraham, Benjamin, Chris, and Dave. What is the probability that both Abraham and Benjamin will be selected?

A. 1/12
B. 1/6
C. 1/3
D. 2/3
E. 5/6

Nidzo · Answer

Probability will be:  2*(1/4 * 1/3)  
 2*(1/12)
2/12
1/6

Anisha1637 · Answer

Probability of selecting Abraham=1/4
Probability of selecting Benjamin=1/3 
Total probability=1/4*1/3 because the sequence of selecting Abraham or Benjamin is not important! 
Therefore, Probability= 1/12

IMO A

Posted from my mobile device

ManyataM · Answer

IMO the answer is option B
2 people need to be selected so,
AB
CD
AC
AD
BC
BD 
AB and be sleceted in one way out of 6
So , 1/6 is the answer

Posted from my mobile device

gmatlover1010 · Answer

\frac{2C2}{4C2} = \frac{1}{6}

4C2 is selecting 2 from 4.. 
2C2 is selecting both A and B.
Option B

MathRevolution · Answer

First A and then B:

=> P(Abraham) =  \frac{1}{4 }

=> P(Benjamin) =  \frac{1}{3}

=> P (both B and A) =  \frac{1}{4}  *  \frac{1}{3}  =  \frac{1}{12}

First B and then A:

=> P(Benjamin) =  \frac{1}{4}

=> P(Abraham) =  \frac{1}{3}

=> P (both B and A) =  \frac{1}{4}  *  \frac{1}{3}  =  \frac{1}{12}

Overall Probability:   \frac{1}{12}   +   \frac{1}{12}   =   \frac{1}{6}

Answer B

NishantTiwary · Answer

1st time: We can pick anyone from the TWO viz = 2/4 
2nd time: Now we need only one among them viz = 1/3 (with replacement)
1st time AND 2nd time = 2/4 * 1/3 = 1/6

IMO B

2 people are to be selected from Abraham, Benjamin, Chris, and Dave.

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2 people are to be selected from Abraham, Benjamin, Chris, and Dave.

Prep Toolkit

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