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2 people are to be selected from Abraham, Benjamin, Chris, and Dave.

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Bunuel
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2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink] New post   18 May 2021, 07:30
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2 people are to be selected from Abraham, Benjamin, Chris, and Dave. What is the probability that both Abraham and Benjamin will be selected?

A. 1/12
B. 1/6
C. 1/3
D. 2/3
E. 5/6
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B
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Nidzo
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Re: 2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink] New post   18 May 2021, 07:38
Probability will be: 2*(1/4 * 1/3)
2*(1/12)
2/12
1/6
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Anisha1637
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Re: 2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink] New post   18 May 2021, 07:48
Probability of selecting Abraham=1/4
Probability of selecting Benjamin=1/3
Total probability=1/4*1/3 because the sequence of selecting Abraham or Benjamin is not important!
Therefore, Probability= 1/12

IMO A

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ManyataM
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Re: 2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink] New post   18 May 2021, 08:23
Bunuel wrote:
2 people are to be selected from Abraham, Benjamin, Chris, and Dave. What is the probability that both Abraham and Benjamin will be selected?

A. 1/12
B. 1/6
C. 1/3
D. 2/3
E. 5/6


IMO the answer is option B
2 people need to be selected so,
AB
CD
AC
AD
BC
BD
AB and be sleceted in one way out of 6
So , 1/6 is the answer

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gmatlover1010
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2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink] New post   20 May 2021, 02:27
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\(\frac{2C2}{4C2} = \frac{1}{6}\)

4C2 is selecting 2 from 4..
2C2 is selecting both A and B.
Option B
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Re: 2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink] New post   20 May 2021, 09:58
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First A and then B:

=> P(Abraham) = \(\frac{1}{4 }\)

=> P(Benjamin) = \(\frac{1}{3}\)

=> P (both B and A) = \(\frac{1}{4}\) * \(\frac{1}{3}\) = \(\frac{1}{12}\)


First B and then A:

=> P(Benjamin) = \(\frac{1}{4}\)

=> P(Abraham) = \(\frac{1}{3}\)

=> P (both B and A) = \(\frac{1}{4}\) * \(\frac{1}{3}\) = \(\frac{1}{12}\)

Overall Probability: \(\frac{1}{12}\) + \(\frac{1}{12}\) = \(\frac{1}{6}\)

Answer B
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NishantTiwary
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Re: 2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink] New post   03 Jun 2021, 04:11
1st time: We can pick anyone from the TWO viz = 2/4
2nd time: Now we need only one among them viz = 1/3 (with replacement)
1st time AND 2nd time = 2/4 * 1/3 = 1/6

IMO B
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Re: 2 people are to be selected from Abraham, Benjamin, Chris, and Dave. [#permalink]
03 Jun 2021, 04:11
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