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# 2 triangles

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Manager
Joined: 04 Dec 2008
Posts: 97

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09 Jun 2009, 07:41
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Pls. explain. Thks!

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Director
Joined: 03 Jun 2009
Posts: 757
Location: New Delhi
WE 1: 5.5 yrs in IT

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09 Jun 2009, 08:23
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These are similar triangles. Similar triangles have sides in the same ratio.
let height of triangles be h and H

Now, for smaller triangle, side s corresponds to height h
implies, side S corresponds to height H = h/s * S

Area of small triangle = 1/2*s*h
Area of larger triangle = 1/2*S*H = 1/2 *S* (h/s *S)

Given area of larger is twice area of smaller, hence
1/2 *S* (h/s *S) = 2 * (1/2 * s*h) --- solve this
or, S = s√2

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Intern
Joined: 04 Mar 2008
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09 Jun 2009, 10:18
agree to the above explanation. The answer is C.
Manager
Joined: 28 Jan 2004
Posts: 199
Location: India

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10 Jun 2009, 20:27
Since both triangles are similar , it does not matter what are the values of angles X,Y,Z.I assumed all to be 60 so it becomes an equilateral triangle.
Area of small triangle ,A1= (sqrt(3)s^2)/4
Area of Large triangle,A2 = (sqrt(3)S^2)/4
According to question,
A2 = 2A1
which easily gives S=sqrt(2)s

I followed this approach to avoiad calculating height (unnecessary calculation)

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: 2 triangles   [#permalink] 10 Jun 2009, 20:27
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# 2 triangles

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