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200^2 – 2(200)(199) + 199^2 =

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200^2 – 2(200)(199) + 199^2 =  [#permalink]

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New post Updated on: 18 Sep 2012, 06:15
4
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

98% (00:57) correct 3% (02:26) wrong based on 73 sessions

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Originally posted by carcass on 17 Sep 2012, 15:23.
Last edited by Bunuel on 18 Sep 2012, 06:15, edited 1 time in total.
Edited the question.
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Re: 200² – 2(200)(199) + 199² =  [#permalink]

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New post 17 Sep 2012, 15:33
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Re: 200^2 − 2(200)(199) + 199^2 =  [#permalink]

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New post 04 Mar 2017, 23:53
SajjadAhmad wrote:
200^2 − 2(200)(199) + 199^2 =

(A) −79,201
(B) −200
(C) 1
(D) 200
(E) 79,999


\(200^2 − 2(200)(199) + 199^2 = ( 200 - 199 )^2\)

( 200 - 199 )^2 = 1^2

Thus, answer must be (C) 1

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Re: 200^2 − 2(200)(199) + 199^2 =  [#permalink]

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New post 20 Oct 2018, 08:37
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Re: 200^2 − 2(200)(199) + 199^2 =   [#permalink] 20 Oct 2018, 08:37
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