SajjadAhmad wrote:

\(\frac{3 ⋅ 3 ⋅ 3 ⋅ 3}{9 ⋅ 9 ⋅ 9 ⋅ 9}\)=

(A) \(\frac{1}{3}\)^4

(B) \(\frac{1}{3}\)^3

(C) 1/3

(D) 4/9

(E) 4/3

Exponents\(\frac{3 ⋅ 3 ⋅ 3 ⋅ 3}{9 ⋅ 9 ⋅ 9 ⋅ 9}=\)

\(\frac{3^4}{(3^2)^4}=\frac{3^4}{3^8}= \frac{1}{3^{(8-4)}}= \frac{1}{3^4}=(\frac{1}{3})^4\)

Cancel factorsFactor out four 3s from

both numerator and denominator, to yield

\(\frac{1 ⋅ 1 ⋅ 1 ⋅ 1}{3 ⋅ 3 ⋅ 3 ⋅ 3}=\frac{1}{3^4} =

(\frac{1}{3})^4\)

Answer A

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