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# (3^(1/2) + 2)(3^(1/2) - 2)

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Math Expert
Joined: 02 Sep 2009
Posts: 53066
(3^(1/2) + 2)(3^(1/2) - 2)  [#permalink]

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08 Oct 2018, 01:39
00:00

Difficulty:

5% (low)

Question Stats:

97% (00:18) correct 3% (00:37) wrong based on 66 sessions

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$$(\sqrt{3} + 2)(\sqrt{3} - 2)=$$

A. $$\sqrt{3}-4$$

B. $$\sqrt{6}-4$$

C. -1

D. 1

E. 2

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Joined: 19 Oct 2013
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Location: Kuwait
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Re: (3^(1/2) + 2)(3^(1/2) - 2)  [#permalink]

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08 Oct 2018, 01:56
1
Bunuel wrote:
$$(\sqrt{3} + 2)(\sqrt{3} - 2)=$$

A. $$\sqrt{3}-4$$

B. $$\sqrt{6}-4$$

C. -1

D. 1

E. 2

Square of a difference = a^2 - b^2 = (a-b)(a+b)

3 - 4 = -1

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Re: (3^(1/2) + 2)(3^(1/2) - 2)  [#permalink]

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08 Oct 2018, 07:58
Bunuel wrote:
$$(\sqrt{3} + 2)(\sqrt{3} - 2)=$$

A. $$\sqrt{3}-4$$

B. $$\sqrt{6}-4$$

C. -1

D. 1

E. 2

$$(\sqrt{3} + 2)(\sqrt{3} - 2)$$

$$= \sqrt{3}*\sqrt{3} - 2*2$$

$$= 3 - 4$$

$$= -1$$,Answer must be (C)
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Abhishek....

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Re: (3^(1/2) + 2)(3^(1/2) - 2)   [#permalink] 08 Oct 2018, 07:58
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