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# (3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =

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Joined: 02 Sep 2009
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(3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =  [#permalink]

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04 Nov 2014, 09:43
1
2
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Difficulty:

5% (low)

Question Stats:

94% (01:25) correct 6% (01:36) wrong based on 167 sessions

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Tough and Tricky questions: Exponents.

$$(3^{5x} + 3^{5x} + 3^{5x})(4^{5x} + 4^{5x} + 4^{5x} + 4^{5x}) =$$

A. 12^(5x + 1)
B. 3^(15x) + 4^(20x)
C. 25^(5x)
D. 7^(35x)
E. 25^(5x+1)

Kudos for a correct solution.

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Re: (3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =  [#permalink]

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10 Nov 2014, 02:21
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$$(3^{5x} + 3^{5x} + 3^{5x})(4^{5x} + 4^{5x} + 4^{5x} + 4^{5x}) = 3 * 3^{5x} * 4 * 4^{5x}$$

$$= 3^{5x+1} * 4^{5x+1} = (3*4)^{5x+1} = 12^{5x+1}$$

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##### General Discussion
Manager
Joined: 27 May 2014
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Re: (3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =  [#permalink]

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04 Nov 2014, 10:25
1
Factor out (3^(5x)) in the first parentheses and (4^(5x)) in the second parentheses. You get ((3^(5x)(3)) x ((4^5x)(4)). Since you have a common exponent (5x) multiply the basis (3^(5x))*(4^(5x)) = (12^(5x)). Noiw multiply the (3*4). So you get (12^(5x))*(12^1)), add common bases (12^(5x+1))
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Re: (3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =  [#permalink]

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28 Dec 2014, 21:41
(1+1+1)*3^5x+(1+1+1+1)*4^5x=3^(5x+1)+4^(5x+1)=12^(5x+1)
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Re: (3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =  [#permalink]

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25 Nov 2018, 05:28
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: (3^5x + 3^5x + 3^5x)(4^5x + 4^5x + 4^5x + 4^5x) =   [#permalink] 25 Nov 2018, 05:28
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