We are given \(3m + 4b = 756\) in 7 days
(1), and \(11m + 13b = 3008\) in 8 days
(2), and want to solve for the time it will take 7 men with 9 boys to make 2480.
The best strategy here is to make everything in terms of earnings for a single day worked, solve for how much 7 men and 9 boys make in a single day and use that to divide 2480 to see how many days it will take.(1) \(3m + 4b = 756\) in 7 days. Which means that each day they earn \(\frac{756}{7}=108\)
(2) \(11m + 13b = 3008\) in 8 days. Which means that each day they earn \(\frac{3008}{8} = 376\)
Multiplying \(3m + 4b = 108\) through by 2 gives: \(6m + 8b = 216\) (we are missing an extra m+b still)
Subtracting \(6m + 8b = 216\) from \(11m + 13b = 376\) gives: \(5m + 5b = 160\), dividing through by 5 will make it: \(m + b = 32\).
Adding \(m + b = 32\) to \(6m + 8b = 216\) gives: \(7m + 9b = 248\)
Therefore, for 7 men and 9 boys to make 2480, it will take them \(\frac{2480}{248} = 10\) days
Answer B.