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19 Aug 2017, 03:20
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Below PS question is from the official guide.
Figures X and Y above show how eight identical triangular pieces of cardboard were used to form a square and a rectangle, respectively. What is the ratio of the perimeter of X to the perimeter of Y?
(A) 2:3
(B) \sqrt{2} :2
(C) 2 \sqrt{2}:3
(D) 1:1
(E) \sqrt{2}:1
Figures X and Y are attached to this post.
Answer given in official guide - C
Now figure X is a square and it can be derived that the two triangles are isosceles triangles which gives us a 45-45-90 triangle. Now the sides of this triangle should be in the ratio 1:1:\sqrt{2}. So sides of triangle can be a:a:a \sqrt{2}. Where the hypotenuse is a \sqrt{2}. However the explanation in OG considers two legs of triangle as a \sqrt{2}.
Can someone please explain me where I am going wrong?
Attachment:
Figure X and Y.JPG
Figures X and Y above show how eight identical triangular pieces of cardboard were used to form a square and a rectangle, respectively. What is the ratio of the perimeter of X to the perimeter of Y?
(A) 2:3
(B) \sqrt{2} :2
(C) 2 \sqrt{2}:3
(D) 1:1
(E) \sqrt{2}:1
Figures X and Y are attached to this post.
Answer given in official guide - C
Now figure X is a square and it can be derived that the two triangles are isosceles triangles which gives us a 45-45-90 triangle. Now the sides of this triangle should be in the ratio 1:1:\sqrt{2}. So sides of triangle can be a:a:a \sqrt{2}. Where the hypotenuse is a \sqrt{2}. However the explanation in OG considers two legs of triangle as a \sqrt{2}.
Can someone please explain me where I am going wrong?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
19 Aug 2017, 03:25
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GMATMBA5
Below PS question is from the official guide.
Figures X and Y above show how eight identical triangular pieces of cardboard were used to form a square and a rectangle, respectively. What is the ratio of the perimeter of X to the perimeter of Y?
(A) 2:3
(B) \sqrt{2} :2
(C) 2 \sqrt{2}:3
(D) 1:1
(E) \sqrt{2}:1
Figures X and Y are attached to this post.
Answer given in official guide - C
Now figure X is a square and it can be derived that the two triangles are isosceles triangles which gives us a 45-45-90 triangle. Now the sides of this triangle should be in the ratio 1:1:\sqrt{2}. So sides of triangle can be a:a:a \sqrt{2}. Where the hypotenuse is a \sqrt{2}. However the explanation in OG considers two legs of triangle as a \sqrt{2}.
Can someone please explain me where I am going wrong?
Attachment:
Figure X and Y.JPG
Figures X and Y above show how eight identical triangular pieces of cardboard were used to form a square and a rectangle, respectively. What is the ratio of the perimeter of X to the perimeter of Y?
(A) 2:3
(B) \sqrt{2} :2
(C) 2 \sqrt{2}:3
(D) 1:1
(E) \sqrt{2}:1
Figures X and Y are attached to this post.
Answer given in official guide - C
Now figure X is a square and it can be derived that the two triangles are isosceles triangles which gives us a 45-45-90 triangle. Now the sides of this triangle should be in the ratio 1:1:\sqrt{2}. So sides of triangle can be a:a:a \sqrt{2}. Where the hypotenuse is a \sqrt{2}. However the explanation in OG considers two legs of triangle as a \sqrt{2}.
Can someone please explain me where I am going wrong?
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19 Aug 2017, 11:32
Kudos
Bookmarks
GMATMBA5
Below PS question is from the official guide.
Figures X and Y above show how eight identical triangular pieces of cardboard were used to form a square and a rectangle, respectively. What is the ratio of the perimeter of X to the perimeter of Y?
(A) 2:3
(B) \sqrt{2} :2
(C) 2 \sqrt{2}:3
(D) 1:1
(E) \sqrt{2}:1
Figures X and Y are attached to this post.
Answer given in official guide - C
Now figure X is a square and it can be derived that the two triangles are isosceles triangles which gives us a 45-45-90 triangle. Now the sides of this triangle should be in the ratio 1:1:\sqrt{2}. So sides of triangle can be a:a:a \sqrt{2}. Where the hypotenuse is a \sqrt{2}. However the explanation in OG considers two legs of triangle as a \sqrt{2}.
Can someone please explain me where I am going wrong?
Attachment:
Figure X and Y.JPG
Figures X and Y above show how eight identical triangular pieces of cardboard were used to form a square and a rectangle, respectively. What is the ratio of the perimeter of X to the perimeter of Y?
(A) 2:3
(B) \sqrt{2} :2
(C) 2 \sqrt{2}:3
(D) 1:1
(E) \sqrt{2}:1
Figures X and Y are attached to this post.
Answer given in official guide - C
Now figure X is a square and it can be derived that the two triangles are isosceles triangles which gives us a 45-45-90 triangle. Now the sides of this triangle should be in the ratio 1:1:\sqrt{2}. So sides of triangle can be a:a:a \sqrt{2}. Where the hypotenuse is a \sqrt{2}. However the explanation in OG considers two legs of triangle as a \sqrt{2}.
Can someone please explain me where I am going wrong?
Also, please read carefully and follow our RULES OF POSTING. Thank you.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
