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5 coins are tossed. If two of them show heads, then the [#permalink]
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31 Mar 2005, 18:36
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5 coins are tossed. If two of them show heads, then the probability that all 5 coins show head is
a. 1/32
b. 1/10
c. 1/26
d. 1/13
e. none of the above



Director
Joined: 18 Feb 2005
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the 2 coins prob is 1
rest 3 coins prob is (1/2)^3 = 1/8



Manager
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OA on this is C. (1/26)



Director
Joined: 27 Dec 2004
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I got A...what am i doing wrong agian



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Joined: 07 Jul 2004
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Total number of combinations:
0H 5T  1 way
1H 4T  5 ways
2H 3T  10 ways
3H 2T  10 ways
4H 1T  5 ways
5H 0T  1 way
Total # of combinations = 32 ways
Number of combinations that all are heads, is only 1: HHHHH
So Probability = 1/32



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Re: coin [#permalink]
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01 Apr 2005, 10:06
cloaked_vessel wrote: 5 coins are tossed. If two of them show heads, then the probability that all 5 coins show head is
a. 1/32 b. 1/10 c. 1/26 d. 1/13 e. none of the above
Total outcome:2^5=32
Outcome of at least two of them show heads:
Total(1 head)(0 head)=3251=26
Outcome of 5 heads=1
Probability=1/26
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Last edited by HongHu on 01 Apr 2005, 10:50, edited 1 time in total.



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Re: coin [#permalink]
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01 Apr 2005, 10:38
HongHu wrote: cloaked_vessel wrote: 5 coins are tossed. If two of them show heads, then the probability that all 5 coins show head is
a. 1/32 b. 1/10 c. 1/26 d. 1/13 e. none of the above Total outcome:2^5=32 Outcome of at least two of them show heads: Total(1 head)(0 head)=3215=26 Outcome of 5 heads=1 Probability=1/26
why do we have to subtract 5 from 32.



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Joined: 03 Jan 2005
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Sorry, the 1 is for 0 head, and the 5 is for 1 head. I'll edit the post to make it clearer.
Basically the question implies that two of them are heads but the other three can also be heads. So we need to know what probability is for getting at least two heads. It'll be total minus the cases where we only get one head, and where we get no heads.
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Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.



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Re: coin [#permalink]
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01 Apr 2005, 12:04
HongHu wrote: cloaked_vessel wrote: 5 coins are tossed. If two of them show heads, then the probability that all 5 coins show head is
a. 1/32 b. 1/10 c. 1/26 d. 1/13 e. none of the above Total outcome:2^5=32 Outcome of at least two of them show heads: Total(1 head)(0 head)=3251=26 Outcome of 5 heads=1 Probability=1/26
Honghu, how do u know that "If two of them show heads" means "atleast 2 heads"...thx



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There are two explanations for this sentence "two of the coins show heads". One is that exactly two coins are heads. The other is at least two are heads. The next sentence askes "What probability is all coins show heads". You know that means in additional to the two heads, the other coins may show heads too. In other word there would be two or more heads, or at least two heads.
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Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.



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Joined: 13 Jun 2004
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Sorry guys but I don't get this one. the question is :
5 coins are tossed. If two of them show heads, then the probability that all 5 coins show head is ?
We already know that 2 of them showed heads, no ? In my opnion it should be 1/8 becasue there are still 3 toss to make and the events are independant : (1/2)^3
What's wrong with 1/8 ?



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Because it didn't say that the first two throw were heads. It just said that two out of five are heads and we don't know the others.
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Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.



VP
Joined: 13 Jun 2004
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Location: London, UK
Schools: Tuck'08

Thanks Hong Hu, I got it now










