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5 integers, not necessarily distinct, are chosen from the integers [#permalink]
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03 Jan 2018, 05:43
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5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n? A) 7 B) 8 C) 9 D) 15 E) 16 == Message from GMAT Club Team == This is not a quality discussion. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
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Re: 5 integers, not necessarily distinct, are chosen from the integers [#permalink]
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03 Jan 2018, 06:06
saswata4s wrote: 5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n?
A) 7 B) 8 C) 9 D) 15 E) 16 15/16 is 0.9375. This means that the total number from (n+1) to n inclusive equals 16. If 8 is the answer this means there are: (9,8,7,6,5,4,3,2,1,0,1,2,3,4,5,6,7,8) 18 numbers. Shouldn't the answer be 7?



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Re: 5 integers, not necessarily distinct, are chosen from the integers [#permalink]
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03 Jan 2018, 06:18
mohdtaha wrote: saswata4s wrote: 5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n?
A) 7 B) 8 C) 9 D) 15 E) 16 15/16 is 0.9375. This means that the total number from (n+1) to n inclusive equals 16. If 8 is the answer this means there are: (9,8,7,6,5,4,3,2,1,0,1,2,3,4,5,6,7,8) 18 numbers. Shouldn't the answer be 7? Yes agree with mohdtahaif (n+1) & n are inclusive, then total terms in the series=n+(n+1)+1=2n+2 and as 2n+2=16=>n=7



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Re: 5 integers, not necessarily distinct, are chosen from the integers [#permalink]
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03 Jan 2018, 06:51
niks18 wrote: mohdtaha wrote: saswata4s wrote: 5 integers, not necessarily distinct, are chosen from the integers between –(n+1) and n, inclusive, where n is a positive integer. If the probability that the product of the chosen integers is zero is 1 – (0.9375)^5, then what is the value of n?
A) 7 B) 8 C) 9 D) 15 E) 16 15/16 is 0.9375. This means that the total number from (n+1) to n inclusive equals 16. If 8 is the answer this means there are: (9,8,7,6,5,4,3,2,1,0,1,2,3,4,5,6,7,8) 18 numbers. Shouldn't the answer be 7? Yes agree with mohdtahaif (n+1) & n are inclusive, then total terms in the series=n+(n+1)+1=2n+2 and as 2n+2=16=>n=7 why did u take 16 Sent from my iPhone using GMAT Club Forum mobile app



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Re: 5 integers, not necessarily distinct, are chosen from the integers [#permalink]
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03 Jan 2018, 06:58
riniglory wrote: why did u take 16 Hi riniglory, Refer to the earlier solution posted by mohdtahaTotal number of integers is 16 which means (n+1) to n has 16 terms. == Message from GMAT Club Team == This is not a quality discussion. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.




Re: 5 integers, not necessarily distinct, are chosen from the integers
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