51% of people surveyed have played game XYZ...(57% of men

Question

51% of people surveyed have played game XYZ...(57% of men and 42% of women).

From this can we infer the ratio of men to women in the survey?

is it, 3 men: 2 women?

jmaynardj · Answer

51%T = 57%M + 42%W => .51T = .57M + .42W

let's say T = 100 => 51 = .57M + .42W

It seems to me that because we can't compare them directly as a fraction to a number any way you solve it we can't create a ratio (which is a fraction).

Maybe I am missing something. Anybody else see something?

jmaynardj · Answer

I feel like it should be solvable b/c I take the simple case of 50% playing the game and 20% woman and 80% men and I can figure out that when there are 10 total playing we have 4 men and 1 woman. But maybe I am simplifying too much?

vishy007 · Answer

These numbers are not directly divisible

Let us go with 100 member in total

Men playing XYZ 57% of 51 approximately = 30
Men NOT playing XYZ 43% of 49 approximately = 20

We can calculate for women to arrive at their numbers summing to 50

So, the ratio should be close to 1: 1

jmaynardj · Answer

Heh got it:

.51T = .57M + .42W (T = W +M)
.51(M + W) = .57M +.42W => 51M + 51W = 57M + 42W => 9W = 6M => M/W = 3/2

So yes the ratio is 3/2.

vishy007 · Answer

Yes, this solution is perfect jmaynardj.

Even taking the Do Not play... it results the same.

.49 T = .43M +.58W 
49M+49W = 43M + 58W
6M= 9W
M/W=9/6 =3/2

+1

51% of people surveyed have played game XYZ...(57% of men

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