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24 Feb 2018, 00:44
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53% (03:04) correct
47%
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based on 55
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8 people: A, B, C, D, E, F, G, H - are sitting around a circular table, equidistant from each other. All of them are facing the table, so that there are 4 pairs of people who are sitting opposite to each other, facing each other. Who is sitting opposite to A, facing A?
(1) B is sitting exactly 3 places to the right of A, while G is sitting exactly 3 places to the right of H.
(2) C and E are sitting opposite to each other, facing each other. A and H are not adjacent to each other.
(1) B is sitting exactly 3 places to the right of A, while G is sitting exactly 3 places to the right of H.
(2) C and E are sitting opposite to each other, facing each other. A and H are not adjacent to each other.
24 Feb 2018, 02:42
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amanvermagmat
8 people: A, B, C, D, E, F, G, H - are sitting around a circular table, equidistant from each other. All of them are facing the table, so that there are 4 pairs of people who are sitting opposite to each other, facing each other. Who is sitting opposite to A, facing A?
(1) B is sitting exactly 3 places to the right of A, while G is sitting exactly 3 places to the right of H.
(2) C and E are sitting opposite to each other, facing each other. A and H are not adjacent to each other.
(1) B is sitting exactly 3 places to the right of A, while G is sitting exactly 3 places to the right of H.
(2) C and E are sitting opposite to each other, facing each other. A and H are not adjacent to each other.
Instead of trying to solve this abstractly, we'll draw it out.
This is an Alternative approach.
Writing 8 X's in a circle we can SEE that we need to find the person 4 places to the right of A.
(1) our order contains AXXB and HXXG. We can draw this as AHXBGX so that G and A are opposite of as AXHBXG so that A and an unknown are opposite.
Insufficient!
(2) our order contains CXXXE and A-some number of X-H. Similarly to the above, this can be drawn different ways and is insufficient.
Insufficient!
Combined:
Once again using our drawing, we can see that the only place we can put H is in front of A (as otherwise there is no way to put C and E opposite each other)
Sufficient!
(C) is our answer.
27 Aug 2019, 03:11
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For these types of Position-cum-Geometry questions, it is best to follow the approach of Draw and Redraw.
Let's start by jotting down what we know.
We know that there are 8 points on the circle equidistant from each other.
We want to know who is sitting opposite A.
We need the positions of 8 or less number of people to get the answer to the question.
See the attachment for the positions.
Answer is C.
Please give kudos if you liked the solution.
Deepti Singh
Master Trainer - GMAT
Manya - The Princeton Review
Let's start by jotting down what we know.
We know that there are 8 points on the circle equidistant from each other.
We want to know who is sitting opposite A.
We need the positions of 8 or less number of people to get the answer to the question.
See the attachment for the positions.
Answer is C.
Please give kudos if you liked the solution.
Deepti Singh
Master Trainer - GMAT
Manya - The Princeton Review
Attachments
new doc 2019-08-27 15.33.55_1.jpg [ 228.87 KiB | Viewed 16705 times ]
