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# A, B and C are positive integers. Is A > C?

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Director
Joined: 12 Feb 2015
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A, B and C are positive integers. Is A > C?  [#permalink]

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30 Sep 2018, 10:06
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Difficulty:

45% (medium)

Question Stats:

64% (01:12) correct 36% (01:03) wrong based on 11 sessions

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A, B and C are positive integers. Is A > C?
1) A, B and C are distinct factors of 8.
2) B = 4C

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Re: A, B and C are positive integers. Is A > C?  [#permalink]

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30 Sep 2018, 11:36
From statement 1)

We know A, B, and C are distinct factors of 8

So A,B, and C could be 1,2,4 respectively A < C, however if we make it 4,2,1 then A>C

Insufficient.

For 2)

B=4C we have no information on A so insufficient

Now combine

If C = 1 then B = 4 and A could be 2 or 8

A>C yes.

If C = 4 then B = 8 and A could be 1 or 2

A > C no.

Insufficient.

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Re: A, B and C are positive integers. Is A > C?  [#permalink]

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30 Sep 2018, 12:44
CAMANISHPARMAR wrote:
A, B and C are positive integers. Is A > C?
1) A, B and C are distinct factors of 8.
2) B = 4C

$$A,B,C\,\,\, \ge 1\,\,\,\,{\rm{ints}}$$

$${\rm{A}}\,\,\mathop > \limits^? \,\,C$$

Let´s BIFURCATE (1+2) at once, to guarantee the correct answer is (E), indeed.

$$\left( {1 + 2} \right)\,\,\left\{ \matrix{ \,{\rm{Take}}\,\,\left( {A,B,C} \right) = \left( {2,4,1} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\, \hfill \cr \,\,{\rm{Take}}\,\,\left( {A,B,C} \right) = \left( {1,8,2} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\,\,\, \hfill \cr} \right.$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: A, B and C are positive integers. Is A > C? &nbs [#permalink] 30 Sep 2018, 12:44
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