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e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 3019
a, b and c are three distinct integers, greater than 1, such that ....  [#permalink]

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1
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Difficulty:   5% (low)

Question Stats: 81% (01:21) correct 19% (02:30) wrong based on 82 sessions

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a, b and c are three distinct integers, greater than 1, such that the product of these integers is 150. If the greatest common divisor of any two numbers, among the three integers, is 1, then what is the sum of all the three integers?

A. 18
B. 22
C. 30
D. 32
E. 54

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Joined: 07 Dec 2014
Posts: 1229
a, b and c are three distinct integers, greater than 1, such that ....  [#permalink]

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EgmatQuantExpert wrote:
a, b and c are three distinct integers, greater than 1, such that the product of these integers is 150. If the greatest common divisor of any two numbers, among the three integers, is 1, then what is the sum of all the three integers?

A. 18
B. 22
C. 30
D. 32
E. 54

if only one of the integers can be a multiple of 5,
the other two integers can be 2 and 3
2*3*5*5=150
2+3+25=30
C
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Concentration: Sustainability, Marketing
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Re: a, b and c are three distinct integers, greater than 1, such that ....  [#permalink]

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150 = 2*3*5^2

so two no. whose GCD is 1 means they are prime

so sum 2+3+25 = 30 IMO C

EgmatQuantExpert wrote:
a, b and c are three distinct integers, greater than 1, such that the product of these integers is 150. If the greatest common divisor of any two numbers, among the three integers, is 1, then what is the sum of all the three integers?

A. 18
B. 22
C. 30
D. 32
E. 54

To read all our articles:Must read articles to reach Q51

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e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 3019
a, b and c are three distinct integers, greater than 1, such that ....  [#permalink]

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Solution

Given:
We are given that,
• a, b and c are three distinct integers, greater than 1
• abc = 150
• GCD(a, b) = GCD(b, c) = GCD(c, a) = 1

To find:
• We are asked to find the value of a + b + c

Approach and Working:
• We have, abc = 150
o And, 150 can be prime factorized as $$2 * 3 * 5^2$$
o Thus, abc = $$2 * 3 * 5^2$$

• And we are given that GCD(a, b) = GCD(b, c) = GCD(c, a) = 1
o This is possible only when a, b and c do not have any common prime factor

• And if we observe 150 has three distinct prime factors, {2, 3, 5}
o So, a, b and c must have exactly one of these three prime factors in them

Therefore, a + b + c = $$2 + 3 + 5^2 = 30$$

Hence the correct answer is Option C.

Answer: C

_________________ a, b and c are three distinct integers, greater than 1, such that ....   [#permalink] 01 Jan 2019, 22:43
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