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That's an easy question.
1)a-1=b+2
So, a is 3 greater than b. a>b
2)b+2= c-3
So, c is 5 greater than b. c>b
from 1 &2 we conclude c>a
3) c-3= d+4
So, c is 7 greater than d. c>d
C is greatest.option C

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=>

Since \(a – 1 = b + 2,\) we have \(a – b = 3 > 0\) or \(a > b.\)

Since \(b + 2 = c – 3,\) we have \(b = c – 5\) or \(a – b = a – ( c – 5 ) = a – c + 5 = 3\) or \(a – c = -2 < 0.\) Thus we have \(c > a > b.\)

Since \(c – 3 = d + 4,\) we have \(c – d = 7\) and \(c > d.\)

Thus \(c\) is the largest value of \(a, b, c\) and \(d.\)

Therefore, C is the answer.
Answer: C
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