|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
02 Aug 2023, 01:30
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
62% (02:14) correct
38%
(01:54)
wrong
based on 216
sessions
History
Date
Time
Result
Not Attempted Yet
A bag contains five stones, three of which weigh x pounds each and two of which weigh y pounds each. What is the total weight of the stones?
(1) The heaviest combination of three stones has a total weight of 13 pounds.
(2) The lightest combination of three stones has a total weight of 12 pounds.
(1) The heaviest combination of three stones has a total weight of 13 pounds.
(2) The lightest combination of three stones has a total weight of 12 pounds.
04 Aug 2023, 05:13
Kudos
Bookmarks
Bunuel
So the weights of the 5 stones are \(x,x,x\) and \(y,y\).
Total weight \(= 3x+2y \)
(1) The heaviest combination of three stones has a total weight of 13 pounds.
If \(x>y\) then \(3x=13 \)
if \(y>x\) then \(2y+x=13 \\
\)
Clearly it is not possible to get a unique value for \(3x+2y\)
INSUFF.
(2) The lightest combination of three stones has a total weight of 12 pounds.
If \(x>y\) then \(2y+x=12\)
If \(y>x\) then \(3x=12\)
Clearly it is not possible to get a unique value for \(3x+2y\)
INSUFF.
1+2
If \(x>y\)
\(3x=13\) and \(2y+x = 12\)
If \(y>x \)
\(2y+x=13 \)
\(3x=12\)
We can clearly see that it is not possible to get a unique value for \(3x+2y\) even when using both statements together.
INSUFF.
Ans E
Hope its clear.
03 Jan 2026, 06:12
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
